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3 years ago

18+3(9f-13) simplify expression

Mathematics

2 answers:

Svetllana [295]3 years ago

7 0

Answer:

3×(9f-7)

Step-by-step explanation:

step 1 - 18÷3×(9f-13)

step 2 - pulling out like terms

27f-21=3×(9f-7)

final result

3×(9f-7)

Nadusha1986 [10]3 years ago

4 0

Answer:

27f-21

Step-by-step explanation:

18+3(9f-13)

18+27f-39

27f+18-39

27f-21

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11. The student government is selling flowers for homecoming. The project costs them $20 for advertising and

MatroZZZ [7]

Answer:

Step-by-step explanation:

3(n+20) = 3(4+20) = 3(24) = 72

3n+20 = 3(4)+20= 12+20=32

If n represents the amount of flowers they sold, then the correct answer should be 32. The cost for each flower they sold would be 3 x 4 and then add $20 for advertising.

8 0

3 years ago

Please find the result !

Sliva [168]

Answer:

$\displaystyle - \frac{1}{2}$

Step-by-step explanation:

we would like to compute the following limit:

$\displaystyle \lim _{x \to 0} \left( \frac{1}{ \ln(x + \sqrt{ {x}^{2} + 1} ) } - \frac{1}{ \ln(x + 1) } \right)$

if we substitute 0 directly we would end up with:

$\displaystyle\frac{1}{0} - \frac{1}{0}$

which is an indeterminate form! therefore we need an alternate way to compute the limit to do so simplify the expression and that yields:

$\displaystyle \lim _{x \to 0} \left( \frac{ \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right)$

now notice that after simplifying we ended up with a rational expression in that case to compute the limit we can consider using L'hopital rule which states that

$\rm \displaystyle \lim _{x \to c} \left( \frac{f(x)}{g(x)} \right) = \lim _{x \to c} \left( \frac{f'(x)}{g'(x)} \right)$

thus apply L'hopital rule which yields:

$\displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \dfrac{d}{dx} \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right)$

use difference and Product derivation rule to differentiate the numerator and the denominator respectively which yields:

$\displaystyle \lim _{x \to 0} \left( \frac{ \frac{1}{x + 1} - \frac{1}{ \sqrt{x + 1} } }{ \frac{ \ln(x + 1)}{ \sqrt{ {x}^{2} + 1 } } + \frac{ \ln(x + \sqrt{x ^{2} + 1 } }{x + 1} } \right)$

simplify which yields:

$\displaystyle \lim _{x \to 0} \left( \frac{ \sqrt{ {x}^{2} + 1 } - x - 1 }{ (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right)$

unfortunately! it's still an indeterminate form if we substitute 0 for x therefore apply L'hopital rule once again which yields:

$\displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \sqrt{ {x}^{2} + 1 } - x - 1 }{ \dfrac{d}{dx} (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right)$

use difference and sum derivation rule to differentiate the numerator and the denominator respectively and that is yields:

$\displaystyle \lim _{x \to 0} \left( \frac{ \frac{x}{ \sqrt{ {x}^{2} + 1 } } - 1}{ \ln(x + 1) + 2 + \frac{x \ln(x + \sqrt{ {x}^{2} + 1 } ) }{ \sqrt{ {x}^{2} + 1 } } } \right)$

thank god! now it's not an indeterminate form if we substitute 0 for x thus do so which yields:

$\displaystyle \frac{ \frac{0}{ \sqrt{ {0}^{2} + 1 } } - 1}{ \ln(0 + 1) + 2 + \frac{0 \ln(0 + \sqrt{ {0}^{2} + 1 } ) }{ \sqrt{ {0}^{2} + 1 } } }$

simplify which yields:

$\displaystyle - \frac{1}{2}$

finally, we are done!

6 0

3 years ago

Read 2 more answers

F(x)=2x+6

Klio2033 [76]

Answer:

Step-by-step explanation:

F(x) = 2x + 6

G(x) = - 5x - 9

product of F and G .....the product is the result of multiplication

(2x + 6)(-5x - 9) =

-10x^2 - 18x - 30x - 54 =

-10x^2 - 48x - 54 <====

6 0

3 years ago

Read 2 more answers

3b - 13 + 4b = 7b + 1

-BARSIC- [3]

Answer:

There is no solution

Step-by-step explanation:

3 0

3 years ago

What was the impact of the olive branch petition

gizmo_the_mogwai [7]

It failed to bring about peace and only angered King George III

The Olive Branch petition was a final attempt by the colonists to avoid going to war with Britain. The purpose was to appease King George III and prevent the conflict between the colonies and Britain from escalating into a full blown war. However, the king refused to read it. And then came the war.

5 0

3 years ago