Question

Mrs. Kim is teaching a 5th grade class. She is standing 48 feet in front of Lester. Carey is sitting to Lester's right. If Carey and Mrs. Kim are 50 feet apart, how far apart are Lester and Carey?

Answer 1

Lester and Carey are 14 feet apart

Step-by-step explanation:

Mrs. Kim is teaching a 5th grade class

• She is standing 48 feet in front of Lester
• Carey is sitting to Lester's right
• Carey and Mrs. Kim are 50 feet apart

We need to find how far apart Lester and Carey

Look to the attached figure

The positions of Mrs. Kim, Lester, and Carey formed a right triangle

∵ The distance between Mrs. Kim and Carey is 50 feet

∴ The length of the hypotenuse of the Δ = 50 feet

∵ The distance between Mrs. Kim and Lester is 48 feet

∴ The length of one leg of the Δ = 48 feet

The formula of length of the sides of the right Δ is:

$(hypotenuse)^{2}=(leg_{1})^{2}+(leg_{2})^{2}$

Substitute the length of the hypotenuse and the length of the given leg in the formula above

∵ (50)² = (48)² + (leg)²

∴ 2500 = 2304 + (leg)²

- Subtract 2304 from both sides

∴ 196 = (leg)²

- Take square for both sides

∴ 14 = leg

∵ This leg represents the distance between Lester and Carey

∴ The distance between Lester and Carey = 14 feet

Lester and Carey are 14 feet apart

Learn more:

You can learn more about the right triangle in brainly.com/question/1238144

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