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3 years ago

12

Un comerciante compró seis camionetas por $2 310 000. Si quiere obtener una ganancia total de $ 577 500, ¿ En cuanto debe vender

cada camioneta?

1 answer:

Dovator [93]3 years ago

7 0

No tengo ni la menor idea

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Which similarity statement is true?

stepan [7]

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Answer:

(a) ΔWZY ~ ΔWXZ ~ ΔZXY

Step-by-step explanation:

In order for the similarity statement to be correct, the corresponding sides need to be listed in the same order.

A: ΔWZY lists sides in order short leg (WZ), long leg (ZY).

ΔWXZ lists sides in order short leg (WX), long leg (XZ).

ΔZXY lists sides in order short leg (ZX), long leg (XY).

The first similarity statement is correct.

__

You can compare this to an incorrect one, the last one, for example.

ΔYZW lists sides in order long leg (YZ), short leg (ZW).

ΔXZW lists sides in order long leg (XZ), hypotenuse (ZW). Hypotenuse and short leg are not corresponding sides, so the similarity statement is incorrect.

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3 years ago

What is 0.6767 as a simplified fraction

vodka [1.7K]

Answer: 6767/10000

Step-by-step explanation:

Just simplify it by its nearest tenth

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3 years ago

Which of the following scatter plots has a trend line that would lie closest to y = x? A. Scatter plot A B. Scatter plot B C. Sc

Burka [1]

I believe that the answer is C

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3 years ago

Read 2 more answers

For Carolina's birthday, her mom took her and 4 friends to a water park. Carolina's mom paid $40 for 5 student tickets. What was

Law Incorporation [45]

Answer:

The price for one student ticket is $8

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3 years ago

Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced

Butoxors [25]

Answer:

1) $\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

2) $df = c-1 = 2-1$

Where c represent the number of categories c=2

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Tall =30 , Short =20

We need to conduct a chi square test in order to check the following hypothesis:

H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.

H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.

Part 1

So then we know that the expected values would be 25 for each case

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

And if we replace we got:

$\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

Part 2

For this case the degreed of freedom are given by:

$df = c-1 = 2-1$

Where c represent the number of categories c=2

And we can calculate the p value given by:

$p_v = P(\chi^2_{1} >2)=0.157$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(2,1,TRUE)"

7 0

3 years ago