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3 years ago

Nicole ordered a volleyball for $9.75

Mathematics

2 answers:

notsponge [240]3 years ago

8 0

Answer:

the other person is right

you should try putting the WHOLE question

Step-by-step explanation:

kotykmax [81]3 years ago

5 0

That’s Nice!!

I don’t think you copied the WHOLE ENTIRE question. I would suggest resubmitting the question so we can help you with it!!

Have a great day and stay safe and positive!!

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What is the slope of the line?<br><br> no slope<br> 1<br> 0<br> -2

morpeh [17]

Answer:

Step-by-step explanation:

4 0

3 years ago

An angle measures 3.2° less than the measure of its complementary angle. What is the measure of each angle?

cupoosta [38]

Answer:

Step-by-step explanation:

x - measure of angle

x + 3.2° - measure of its complementary angle

Complementary angles adds to 90°

x + x + 3.2° = 90°

2x = 90° - 3.2°

2x = 86.8°

x = 86.8°÷2

x = 43.4°

x+3.2° = 43.4° + 3.2° = 46.6°

4 0

2 years ago

Calculate the slope of the line that passes through the following points:

alina1380 [7]

Answer:

Step-by-step explanation:

Slope is -7--7/1--4

=0/5

7 0

2 years ago

Please help I’ll give brainliest if correct

Ira Lisetskai [31]

Answer:

The value of g(22) = 31

Hence, option D is correct.

Step-by-step explanation:

Given

f(x)= 4x³ – 10

g(x) = 3x - 4 /2

To determine

g(f(2)) = ?

To determine g(f(2)), first, we need to calculate f(2)

so substitute x = 2 in f(x)= 4x³ – 10

f(x)= 4x³ – 10

f(2) = 4(2)³ - 10

f(2) = 32 - 10

f(2) = 22

g(f(2)) = g(22)

now substitute x = 22 in g(x) = [3x - 4] / [2]

g(x) = [3x - 4] / [2]

g(22) = [3(22) - 4] / [2]

g(22) = [66-4] / [2]

g(22) = [62] / [2]

g(22) = 31

g(f(2)) = g(22) = 31

Therefore, the value of g(22) = 31

Hence, option D is correct.

4 0

2 years ago

The city has an average of 13 days of rainfall for April.

zhenek [66]

Using the Poisson distribution, we have that:

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

For this problem, the mean is given as follows:

$\mu = 13$

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859$

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0$

$P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003$

$P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019$

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

6 0

1 year ago