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3 years ago

1.) List all interior angles (see image)

Mathematics

1 answer:

Goryan [66]3 years ago

5 0

Answer:

1. B C F G

2. A+C, B+D, E+G, F+H

3. Alternate Exterior Angles

4. A=105, C=105, D=75, E=75, F=105, G=75, H=105

5. B D E

6. 65

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16. Reasoning What steps would you take to compare 2 kilograms and 3.200 grams

Mars2501 [29]

I would use the metric system and divide or multiply according to the power the metric system unit of measurement is in. Like 2cm to mm.

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3 years ago

What is the solution to the inequality -8x + 4 < -4?

never [62]

Answer:

x > 1

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Step-by-step explanation:

Step 1: Define

-8x + 4 < -4

Step 2: Solve for x

Subtract 4 on both sides: -8x < -8
Divide -8 on both sides: x > 1

Here we see that any value x greater than 1 would work as a solution.

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3 years ago

Starting in the year 1800, the population of the United States was recorded until the year 2000. The data is summarized below wi

krok68 [10]

Answer:

$a = 73.84$ , $b = -23.64$ , $c = 83.97$ , $d = 21.73$

Step-by-step explanation:

1880:

The predicted value is:

$f(80) = 1.363\cdot (80) - 35.2$

$f(80) = 73.84$

The residual value is:

$\Delta f = 50.2 - 73.84$

$\Delta f = -23.64$

1920:

The predicted value is:

$f(120) = 7.8 \cdot 1.02^{120}$

$f(120) = 83.97$

The residual value is:

$\Delta f = 105.7 - 83.97$

$\Delta f = 21.73$

7 0

3 years ago

Read 2 more answers

Select all expressions that are equivalent to -2x - (x+5) + 3

Nuetrik [128]

2x-x+5+3 is the answer hope this helped

7 0

3 years ago

Mathematics achievement test scores for 300 students were found to have a mean and a variance equal to 600 and 3600, respectivel

Zina [86]

Answer:

(a) Approximately 205 students scored between 540 and 660.

(b) Approximately 287 students scored between 480 and 720.

Step-by-step explanation:

A mound-shaped distribution is a normal distribution since the shape of a normal curve is mound-shaped.

Let X = test score of a student.

It is provided that $X\sim N(\mu = 600, \sigma^{2} = 3600)$ .

(a)

The probability of scores between 540 and 660 as follows:

$P(540\leq X\leq 660)=P(\frac{540-600}{\sqrt{3600} }\leq \frac{X-600}{\sqrt{3600} }\leq \frac{660-600}{\sqrt{3600} })\\=P(-1 \leq Z\leq 1)\\= P(Z\leq 1)-P(Z\leq -1)\\=0.8413-0.1587\\=0.6826$

Use the standard normal table for the probabilities.

The number of students who scored between 540 and 660 is:

300 × 0.6826 = 204.78 ≈ 205

Thus, approximately 205 students scored between 540 and 660.

(b)

The probability of scores between 480 and 720 as follows:

$P(480\leq X\leq 720)=P(\frac{480-600}{\sqrt{3600} }\leq \frac{X-600}{\sqrt{3600} }\leq \frac{720-600}{\sqrt{3600} })\\=P(-2 \leq Z\leq 2)\\= P(Z\leq 2)-P(Z\leq -2)\\=0.9772-0.0228\\=0.9544$

Use the standard normal table for the probabilities.

The number of students who scored between 480 and 720 is:

300 × 0.9544 = 286.32 ≈ 287

Thus, approximately 287 students scored between 480 and 720.

3 0

3 years ago