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2 years ago

Round 2.51 to 1 decimal place

Mathematics

2 answers:

Leni [432]2 years ago

8 0

Answer:

2.5

Step-by-step explanation:

It's because 1is less than 5

pychu [463]2 years ago

8 0

Answer:

$\boldsymbol{2.5}$

Step-by-step explanation:

Hi student! Let me help you out on this question.

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<h3> $\dag$ ROUNDING $\dag$ </h3>

When rounding numbers, it's important that you remember these two rules:

If the digit you are asked to round is followed by a digit less than 5, you round down. An example is given below.

$\boldsymbol{3.51=== > 3.5}$ (Rounded to 1 D.P.)

2. If the digit you are asked to round is followed by a digit

greater than or equal to 5, you round up. An example is given

below.

$\boldsymbol{6.25=== > 6.3}$

$\boldsymbol{2.16=== > 2.2}$

Now that we know these two rules, let's round the given number.

$\boldsymbol{2.51=== > ?}$

The digit we are asked to round to (5) is followed by a number less than 5.

$\sf{\therefore,\:we\:round\:down.}$

Thus,

$\boldsymbol{2.51=== > \not? \:2.5}$ . Which is our answer.

Hope that this helped you out! Have a nice day ahead.

Best Wishes!

<em>◈◈-Greetings!-◆◆</em>

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75 months is 6.25001 calendar years.

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3 years ago

Read 2 more answers

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

3 years ago

In the right triangle shown, m of angle N = 30 degrees and MO = 8.<br> How long is NO?

expeople1 [14]

Answer:

Step-by-step explanation: 16

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3 years ago

A cylindrical soup can has a height of 8 in. and a radius of 3in. If the height is doubled on a second soup can, what will be th

kykrilka [37]

Answer:

The ratio of the volumes of the two soup cans is 2.

Step-by-step explanation:

The volume of a cylinder can be written as:

$V=\pi r^2h$

where r is the radius of the base and h is the height.

If the height of the second cylinder doubles the height of th first cylinder, the ratio of volume between the second and the first cylinder is:

$\dfrac{V_2}{V_1}=\dfrac{\pi r^2 h_2}{\pi r^2 h_1}=\dfrac{\pi r^2 (2h)}{\pi r^2 h}=\dfrac{2}{1}=2$

The ratio of the volumes of the two soup cans is 2.

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3 years ago

HELP ILL GIVE BRAINLEY

gulaghasi [49]

Answer: 1/30

Step-by-step explanation:

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Hope it helps <3 :D

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