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Trava [24]
3 years ago
11

Anyone know the answers?

Mathematics
2 answers:
pogonyaev3 years ago
7 0

Answer:

im pretty sure number 3 is yes.

Step-by-step explanation:

15x-2 = 5x+3

subtract 3 from both sides which is now-

15x-5=5x

then now you subtract 15x from both sides which is now-

-5x= -10

now you divide both sides by -5 which will give you 2

i dont know for sure but hopefully this helped

JulijaS [17]3 years ago
3 0

(6 + (-7) / 2 , 7 + (-6) / 2) = ( -1/2 , 1/2)

No santiago is incorrect, the midpoint G is at (-1/2 , 1/2)

15x - 2 + 5x + 3 = 5

20x + 1 = 5

20 x = 4

x = 2

No, Q is not the midpoint, because it is not halfway between P and R

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Y>= -5x + 8 what is m?​
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Answer:

The slope = -5

Step-by-step explanation:

y ≥ -5x + 8

Look at the problem as y = -5x + 8 and compare to the slope intercept form. The slope = -5

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3 years ago
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Jack’s school bag contains 8 books each of weight 3/8 pounds, and 6 folders of weight 1/2 pound. b) What fraction of the total w
kirill115 [55]

Answer:

6 pounds

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7 0
2 years ago
If \dfrac{x-1}{3}=k 3 x−1 ​ =kstart fraction, x, minus, 1, divided by, 3, end fraction, equals, k and k=3k=3k, equals, 3, what i
earnstyle [38]
For this case we have the following expression:
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 Substituting the value of k = 3 we have:
 (x-1) / (3) = 3
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The value of x is given by:
 
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7 0
3 years ago
Surface area of a pyramid
Ede4ka [16]

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To find the surface area of a regular triangular pyramid, we use the formula SA = A + (3/2)bh, where A = the area of the pyramid's base, b = the base of one of the faces, and h = height of one of the faces.

We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area.

To find surface area for a rectangular prism, use the formula SA = 2ab + 2bc + 2ac, where a is the width, b is the height, and c is the length. If you're trying to find the surface area of a triangular prism, use the formula SA = 2a + ph, where a is the area of the triangle, p is the perimeter, and h is the height

Hope that was helpful.Thank you!!!

7 0
4 years ago
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