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navik [9.2K]
3 years ago
13

A) Identify where he made the error

Mathematics
1 answer:
Stels [109]3 years ago
3 0

Answer: Don’t know duidjdjdjdhdhd

Step-by-step explanation:

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Help! Due TODAY!!!!!!!!
koban [17]
Length of bottom is four width is four height is also two
Top has a length of 2 height of three and a width of four
5 0
3 years ago
Read 2 more answers
There is a bag filled with 5 blue and 4 red marbles.
Delvig [45]

Answer:

8/18=4/9

Step-by-step explanation:

since it there is 1/6 for red marbles and 5/18 for blue marbles it works because it is 8*9=72 for the denominator and 4*3=12 so it is 12/72=1/6 and for blue it is 5/18 because it is 5*4=20 and 20/72=10/36=5/18 so it is 1/6+5/18=8/18=4/9

4 0
3 years ago
To offset college expenses, at the beginning of your freshman year you obtain a nonsubsidized student loan for $15,000. Interest
soldier1979 [14.2K]

Answer:

15000(1.003425)^12t ;

4.11%

4.188%

Step-by-step explanation:

Given that:

Loan amount = principal = $15000

Interest rate, r = 4.11% = 0.0411

n = number of times compounded per period, monthly = 12 (number of months in a year)

Total amount, F owed, after t years in college ;

F(t) = P(1 + r/n)^nt

F(t) = 15000(1 + 0.0411/12)^12t

F(t) = 15000(1.003425)^12t

2.) The annual percentage rate is the interest rate without compounding = 4.11%

3.)

The APY

APY = (1 + APR/n)^n - 1

APY = (1 + 0.0411/12)^12 - 1

APY = (1.003425)^12 - 1

APY = 1.04188 - 1

APY = 0.04188

APY = 0.04188 * 100% = 4.188%

7 0
3 years ago
Find x<br><br><br><br><br> Thanks for the help in advance!
Marina86 [1]

I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

AH=2,\quad HB=6,\quad AC=x

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}

If we solve the first two equations for y squared, we have

y^2=x^2-4\\y^2=z^2-36

And we can deduce

z^2 = x^2+32

So that the third equation becomes

x^2+x^2+32=64 \iff 2x^2 = 32 \iff x^2=16 \iff x=4

(we can't accept the negative root because negative lengths make no sense)

7 0
3 years ago
PLEASE HELP!! I NEED HELP WITH THIS PROBLEM!
valkas [14]
His basic salary is $ 2,500, his commission on sales is 3% (on sales only)
At the end of te month he got $3,040

Let x be the TOTAL sales performed during this month, so the money generated from sales (only) is (x).(3%), Hence the equation:

2500 + (x).(3%) = 3040
2500 + x(0.03) = 3040
x(0.03) = 3040-2500
x(0.03) = 540

and x = 540/0.03
x = $18,000


5 0
4 years ago
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