First reduce it.
10:7 In a sense that is about as far down as you can go
You could however make it 1 3/7 to 1
Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.

To find:
The theorem which shows that
.
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
Uh oh, this is a problem right ok whta is thus