This integer is x17, or xx17, or xxx17
all the digits make a sum of 17, ?+1+7=17, ?=9. the other digits need to make a sum of 9
of the numbers from 1-9, only 1 multiplying 7 will result in a 7 in the one's place, so my reasoning is that the ending 17 needs to remain independent, that is, we need to look for the first digits that will make a sum of 9 AND divisible by 17. Keep counting by 17,
17, 34, 51, 68, 85, 102, 119, 136, 153
we can see that the first sum of 9 happens when 17*9=153, 1+5+3=9
so the smallest integer that satisfies all the conditions is 15317
Please let me know if you find another way to figure it out, or if there is a smaller interger
Answer:
It can be written as:
(9m)(9m)(9m)(9m)
Step-by-step explanation:
Answer 5!
Explanation;;
your dividing 15 among 3 people. Since 3 x 5 is 15, then when you divide you should get 5. 5 + 5 + 5 is 15!
please bark brainlist!
Answer: The below figure shows the graph of f(x).
Explanation: Given function,
Since, here three conditions are given,
In first case for values x<-5 , f(x)=5, so we get a line y=5 parallel to x-axis which passes through point (0,5).
In second case, for values , f(x) =-2, so we get a line y=-2 parallel to x-axis which passes through point (0,-2).
In third case, for values x>6, f(x)=1, so we get a line y=1 parallel to x-axis which passes through point (0,1).
Thus, these three lines make the piecewise-defined function f(x).