Problem 1 is fully factored as each term is a binomial raised to some exponent. If the exponent isn't showing up, it's because it is 1. Recall that x^1 = x.
Problem 2 can be factored further because x^2-8x+16 factors to (x-4)(x-4) or (x-4)^2. To get this factorization, you find two numbers that multiply to 16 and add to -8. Those two numbers are -4 and -4 which is where the (x-4)(x-4) comes from. Overall, the entire thing factors to (x-4)^2*(x+3)*(x-2)
Problem 3 is a similar story. We can factor x^2-1 into (x-1)(x+1). I used the difference of squares rule here. Or you can think of x^2-1 as x^2+0x-1, then find two numbers that multiply to -1 and add to 0. Those two numbers are +1 and -1 which leads to (x+1)(x-1). So the full factorization is (x-1)(x+1)(x+1)(x-4) which is the same as (x-1)(x+1)^2(x-4)
Answer:
Graph the equation by plotting three
points. If all three are correct, the line
will appear.
2y = -x + 2
Step-by-step explanation:
We know the area of a circle is
That is when the cricle is 360 degrees full, so another formula is
If we the find the area of the sector with angle x, then that formula will be
Answer:
B
Step-by-step explanation:
because the numbers 0-9 consist of 10 numbers,
having a 70% chance of success means that out of the 10 numbers, 7 are correct.
thus, choice B is correct as it have 7 numbers in it
(rmb to count "0" as a number!)
