A circle has a radius of 3. An arc in this circle has a central angle of 60 degrees. What is the length of the arc?

PLS HELP ME ASAP WITH 3!! (MUST SHOW WORK!!) + LOTS OF POINTS!

Olenka [21]

The correct answer is d

4 0

4 years ago

The cost of ice cream at Oh Wow Cow is $3.99 plus $0.50 per topping. Write an equation in two variables to represent how much an

Vlada [557]

Answer:

y = 3.99 + 0.5x

Step-by-step explanation:

y = 3.99 + 0.5x

y = total cost

x = amount of toppings

4 0

3 years ago

Read 2 more answers

find the measure of the central angle of a circle if it's minor are length is 14π and the radius is 18 inches

MrMuchimi

Step-by-step explanation:

Length of arc of a circle is given as:

$l = \frac{ \theta}{360 \degree} \times 2\pi \: r \\ \\ \therefore \: 14\pi = \frac{ \theta}{360 \degree} \times 2\pi \: \times 18 \\ \\ \therefore \:\theta = \frac{14\pi \times \: 360 \degree }{2\pi \: \times 18} \\ \\ \therefore \:\theta = \frac{7 \times \: 360 \degree }{18} \\ \\ \therefore \:\theta = 7 \times \: 20 \degree \\ \\ \huge \red{ \boxed{\therefore \:\theta = 140 \degree}}$

Thus, the measure of central angle is 140°.

7 0

3 years ago

Solve each equation (Polynomial equations)

lesya [120]

${ {e}^{x} }^{2} = \frac{1}{ {e}^{2} } \times {e}^{3x} \\ \Leftrightarrow { {e}^{x} }^{2} = {e}^{ 3x} \times {e}^{ - 2} \\ \Leftrightarrow { {e}^{x} }^{2} = {e}^{3x - 2} \\ \Leftrightarrow {x}^{2} = 3x - 2 \\ \Leftrightarrow {x}^{2} - 3x + 2 = 0 \\ \Leftrightarrow (x - 1)(x - 2) = 0 \\ x = 1 \: \vee \: x = 2 \\ \\ {32}^{ {x}^{2} - 2x } = \frac{1}{ {4}^{x} } \\ \Leftrightarrow {( {2}^{5} )}^{ {x}^{2} - 2x } = {2}^{ - 2x} \\ \Leftrightarrow {2}^{5 {x}^{2} - 10x } = {2}^{ - 2x} \\ \Leftrightarrow 5 {x}^{2} - 10x = - 2x \\ \Leftrightarrow 5 {x}^{2} - 8x = 0 \\ \Leftrightarrow x(5x - 8) = 0 \\ \Leftrightarrow x = 0 \: \vee \: x = \frac{8}{5} \\ \\ { {e}^{x} }^{3} = {2}^{2x} \\ \Leftrightarrow {x}^{3} = ln( {2}^{2x} ) \\ \Leftrightarrow {x}^{3} - 2x ln(2) = 0 \\ \Leftrightarrow x( {x}^{2} - 2 ln(2) ) = 0 \\ \Leftrightarrow x = 0 \:\vee \: {x}^{2} = 2 ln(2) \\ \Leftrightarrow x = 0 \:\vee \: x = \sqrt{2 ln(2) } \:\vee \: x = - \sqrt{2 ln(2) }$

8 0

4 years ago

How do you do this question?

vaieri [72.5K]

Answer:

(-∞, -2), (-2, -0.618), and (1.618, 3)

Step-by-step explanation:

The red plus (+) signs indicate the regions in which the function is concave up, and the red negative (-) signs indicate the regions in which the function is concave down.

Note that the sign of the concavity changes at an inflection point.

Let's examine the intervals given.

(-∞, -2): Yes, concave up.

(-∞, -1.17): No. Concave up in (-∞, -2) but concave down in (-2, -1.17).

(-2, 0): No. Concave down in (-2, -1.17) but increasing in (-1.17, 0.0).

(-1.17, 0.689): Yes. Concave up.

(-0.618, 1.618): No. Concave up in (-0.618, 0.689) but concave down in (0.689, 1.618).

(0, 3): No. Concave up in (0, 0.689), concave down in (0.689, 2.481), and concave up in (2.481, 3).

(2.481, ∞): Yes. Concave up.

The three intervals that are concave up are (-∞, -2), (-1.17, -0.689), and (2.481, ∞).

4 0

3 years ago