( x + 1 )/ 3 = x + 2
Multiply 3 on both sides
x + 1 = 3x + 6
Subtract 6 on both sides
x - 5 = 3x
Subtract x from both sides
-5 = 2x
Divide 2 from both sides
x = -2.5
The change is 580 feet per hour.
11049 - 7569 is 3480.
Then 3480 ÷ 6 is 580.
Answer:
The class 35 - 40 has maximum frequency. So, it is the modal class.
From the given data,








MODE
- Most precisely, mode is that value of the variable at which the concentration of the data is maximum.
MODAL CLASS
- In a frequency distribution the class having maximum frequency is called the modal class.


Where,






