Answer: Answer:The solution to the given system of equations is (2.8,0.1)
Step-by-step explanation: I got it correct on the Unit Test
Let x and y be the 2 parts of 15 ==> x + y=15 (given)
Reciprocal of x and y ==> 1/x +1/y ==> 1/x + 1/y = 3/10 (given)
Let's solve 1/x + 1/y = 3/10 . Common denominator = 10.x.y (reduce to same denominator)
==> (10y+10x)/10xy = 3xy/10xy ==> 10x+10y =3xy
But x+y = 15 , then 10x+10y =150 ==> 150=3xy and xy = 50
Now we have the sum S of the 2 parts that is S = 15 and
their Product = xy =50
Let's use the quadratic equation for S and P==> X² -SX +P =0
Or X² - 15X + 50=0, Solve for X & you will find:
The 1st part of 15 is 10 & the 2nd part is 5
To reduce a fraction, divide the numerator and the denominator equally until they reach the simplest whole number possible.
In this case, the numerator (720) and the denominator (1080) can both be divided by 360 to get 2/3, our reduced fraction.
The length of rope(consist of 3 pieces)=9*2=18m
One piece=18/3=6m
Pls mark me as the Brainliest as I really need it!
Answer:
x-intercept = (8,0)
y-intercept = (0,20)
