The equation of the line of the other leg of the right triangle if it shares the vertice of (10,0) is y = -1/3x + 10/3
<h3>How to find the equation of a line?</h3>
The equation of a line in slope-intercept form is expressed as y = mx + b
where
m is the slope
b is the y-intercept
Given the coordinate points (-2, 4) and (10, 0)
Find the slope
Slope = -4/12
Slope = -1/3
Determine the y-intecept
0 = -1/3(10) + b
b = 10/3
Determine the equation
y = -1/3x + 10/3
Hence the equation of the line of the other leg of the right triangle if it shares the vertice of (10,0) is y = -1/3x + 10/3
Learn more on equation of a line here: brainly.com/question/13763238
Answer:
4
Step-by-step explanation:
the Fundamental Theorem of Algebra states that for any polynomial of degree n, there are n roots, some of which may be complex
The polynomial shown is of degree 4 ( highest exponent of x )
Hence the polynomial has 4 roots/ zeros