Please help! Will give brainliest to correct answer!

Pls help i am on a timer

salantis [7]

Answer: (x-6)(x+1)

Step-by-step explanation:

Sum : x2 − 5 x- 6

x2 + x-=6 x − 6

factor pair: x 2 + x − 6 x − 6

x( x+ 1 ) − 6 ( x + 1 )

rewrite from: x (x + 1 ) − 6 ( x + 1 )

(x-6)(x+1)

8 0

3 years ago

Read 2 more answers

Meteorologists in Texas want to increase the amount of rain delivered by thunderheads by seeding the clouds. Without seeding, th

Dafna11 [192]

Answer:

There is no significant difference in the amount of rain produced when seeding the clouds.

Step-by-step explanation:

Assuming that the amount of rain delivered by thunderheads follows a distribution close to a normal one, we can formulate a hypothesis z-test:

Null Hypothesis

$\bf H_0$ : Average of the amount of rain delivered by thunderheads without seeding the clouds = 300 acrefeet.

Alternative Hypothesis

$\bf H_a$ : Average of the amount of rain delivered by thunderheads by seeding the clouds > 300 acrefeet.

This is a right-tailed test.

Our z-statistic is

$\bf z=\frac{370.4-300}{300.1/\sqrt{30}}=1.2845$

We now compare this value with the z-critical for a 0.05 significance level. This is a value $\bf z^*$ such that the area under the Normal curve to the left of $\bf z^*$ is less than or equal to 0.05

We can find this value with tables, calculators or spreadsheets.

In Excel or OpenOffice Calc use the function

NORMSINV(0.95)

an we obtain a value of

$\bf z^*$ = 1.645

Since 1.2845 is not greater than 1.645 we cannot reject the null, so the conclusion that can be drawn when the significance level is 0.05 is that there is no significant difference in the amount of rain produced when seeding the clouds.

8 0

3 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

D = a person has the disease

X = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

3 years ago

Evaluate this expression (-7--9)*(8+2)

Marizza181 [45]

Before we get started, it is good to remember PEMDAS - the acronym that tells you the order to carry out equations.

P = parentheses
E = exponents
M = multiplication
D = division
A = addition
S = subtraction

Knowing this, we should start by doing the equations within each parentheses.

$(-7 - -9) *(8 + 2)$
$(2) *(10)$

So we did the addition and subtraction pieces within each group leaving us with the above equation. Now let's multiply:

$(2)*(10) = 20$

20 is the answer.

5 0

3 years ago

I need help on this one and the one at the bottom

KiRa [710]

The last awnser is 15x + 2 and the first one is explained below:
65 X 1.5 = 97.5
97.5 + 95 = 192.5
192.5 is awnser
If you want me to explain in more detail comment on my user i will check my notifications and help you out !!! :D
PEACE YALL

3 0

3 years ago