Answer:
The correct code for this question:
g=float(input("Enter your English test grade:")) #take input from user.
#check conditions
if (g>=100 and g<=90):
print ("A")
#g greater then equal to 100 and less then equal to 90.
if (g>=89 and g<=80):
print("B")
#g greater then equal to 89 and less then equal to 80.
if (g>=79 and g<=70):
print("C")
#g greater then equal to 79 and less then equal to 70.
if (g>=69 and g<=65):
print("D")
#g greater then equal to 69 and less then equal to 69.
if(g<=64):
print("F")
#g less then equal to 64.
else:
print ("Not a grade")
#not a grade or fail.
Explanation:
In this program, we use to take a value from the user and check the value from the various conditions. To check all the condition we use if-else statement and AND operator that check to the range to together.
If -else is a conditional operator. In that, If block is used to check the true part and else part takes false value, and AND is a logical operator that check the two range together
Answer:
The answer is below
Explanation:
The amount of power dissipated by a processor is given by the formula:
P = fCV²
Where f = clock rate, C = capacitance and V = Voltage
For the old version of processor with a clock rate of f, capacitance C and voltage of V, the power dissipated is:
P(old) = fCV²
For the new version of processor with a clock rate of 20% increase = (100% + 20%)f = 1.2f, capacitance is the same = C and voltage of 20% increase = 1.2V, the power dissipated is:
P(new) = 1.2f × C × (1.2V)² = 1.2f × C × 1.44V² =1.728fCV² = 1.728 × Power dissipated by old processor
Hence, the new processor is 1.728 times (72.8% more) the power of the old processor
<span>Beside homework, what products can you use for personal use? Identify three uses and briefly describe.
</span>
The connector for ethernet cables is called RJ45. for phone jack is RJ11. Although they look the same, the RJ11 has only 4 leads, as opposed to 9 leads in RJ45. Also, RJ11 is not as wide as RJ45, so the connector does not fit.
Even if it would, the signals would be totally incompatible, so no success can be expected.
Answer:
a. (210^6)((210^7)/(2.510^8)) = 1.610^5 bits or 160,000 bits
b. 1.6*10^5 bits or 160,000 bits
c. Bandwidth delay product of link is maximum number of bits that can be in the link
d. Width of bit = Length of link / bandwidth-delay product so 1 bit is 125 meters long. Yes, this is longer than a football field.
e. Width of bit = s/R
Hope this helps :)
