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abruzzese [7]
3 years ago
7

Complete the second clause of the following Prolog program for member/2 where member(X, Y) checks whether X is an element (a mem

ber) of a list Y. member(X,[X|R]). member(X,[Y|R]) :- ____________.A. member(X,R).
B. member(X,Y).
C. member(_,R).
D. member(Y,R).
E. member(X,Y).
Computers and Technology
1 answer:
Nadusha1986 [10]3 years ago
4 0

Answer:

The answer is "Option A"

Explanation:

In the given program code, two-member "X, Y" is used, in which X is an element of the list and Y is the list. In this another variable R declares, that store a number for the match, in this question choice "A" is correct because it uses an element and variable "R" for check and wrong choices can be described as follows:

  • In option B, in this two-parameter is used, in which one is an element and one is the list, that's why it is incorrect.
  • In option C, It is wrong because there is no underscore variable.
  • Option D and Option E both were wrong because in this list is passed as the parameter.
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2. Write a simple program in C++ to investigate the safety of its enumeration types. Include at least 10 different operations on
erastovalidia [21]

Answer:

Check the explanation

Explanation:

To solve the question above, we will be doing some arithmetic and bit wise operations on enum values. in addition to that, we are asserting the array with INTCOUNT  and also printing the size of array i.e 12 and we are adding BIG_COUNT enum value to 5 and the result is 25.

#include<stdio.h>

enum EnumBits

{

ONE = 1,

TWO = 2,

FOUR = 4,

EIGHT = 8

};

enum Randoms

{

BIG_COUNT = 20,

INTCOUNT = 3

};

int main()

{

// Basic Mathimatical operations

printf("%d\n",(ONE + TWO)); //addition

printf("%d\n",(FOUR - TWO)); //subtraction

printf("%d\n",(TWO * EIGHT)); //multiplication

printf("%d\n",(EIGHT / TWO)); //division

// Some bitwise operations

printf("%d\n",(ONE | TWO)); //bitwise OR

printf("%d\n",(TWO & FOUR)); //bitwise AND

printf("%d\n",(TWO ^ EIGHT)); //bitwise XOR

printf("%d\n",(EIGHT << 1)); //left shift operator

printf("%d\n",(EIGHT >> 1)); //right shift operator

// Initialize an array based upon an enum value

int intArray[INTCOUNT]; // declaring array

// Have a value initialized be initialized to a static value plus

int someVal = 5 + BIG_COUNT; //adding constant and BIG_COUNT variable

printf("%d\n",someVal); //value will be 25

printf("%d",sizeof(intArray)); //value will be 12

return 0;

}

Kindly check the attached image below for the Code and Output Screenshots:

6 0
3 years ago
Which statement best describes the problem statement below?
Vinil7 [7]

Answer:

dont click on his link it has virus

6 0
3 years ago
The data below represents the yearly earnings (in $1000s of dollars) that high school and college (BS) graduates earn at a small
Taya2010 [7]

Answer:

library(moments)

library(readxl)

Exam1Q1 <- read_excel("Exam1Q1.xlsx")

View(Exam1Q1)

## Warning in system2("/usr/bin/otool", c("-L", shQuote(DSO)), stdout = TRUE):

## running command ''/usr/bin/otool' -L '/Library/Frameworks/R.framework/

## Resources/modules/R_de.so'' had status 1

plot(density(Exam1Q1$Highschool))

gostino.test(Exam1Q1$Highschool)

##  

##  D'Agostino skewness test

##  

## data:  Exam1Q1$Highschool

## skew = -0.24041, z = -0.69269, p-value = 0.4885

## alternative hypothesis: data have a skewness

agostino.test(Exam1Q1$BS)

##  

##  D'Agostino skewness test

##  

## data:  Exam1Q1$BS

## skew = 0.53467, z = 1.49330, p-value = 0.1354

## alternative hypothesis: data have a skewness

anscombe.test(Exam1Q1$Highschool)

##  

##  Anscombe-Glynn kurtosis test

##  

## data:  Exam1Q1$Highschool

## kurt = 2.56950, z = -0.29677, p-value = 0.7666

## alternative hypothesis: kurtosis is not equal to 3

anscombe.test(Exam1Q1$BS)

##  

##  Anscombe-Glynn kurtosis test

##  

## data:  Exam1Q1$BS

## kurt = 3.6449, z = 1.2599, p-value = 0.2077

## alternative hypothesis: kurtosis is not equal to 3

t.test(Exam1Q1$Highschool,Exam1Q1$BS, var.equal = T)

##  

##  Two Sample t-test

##  

## data:  Exam1Q1$Highschool and Exam1Q1$BS

## t = 0.16929, df = 76, p-value = 0.866

## alternative hypothesis: true difference in means is not equal to 0

## 95 percent confidence interval:

##  -1.131669  1.341926

## sample estimates:

## mean of x mean of y  

##  39.51282  39.40769

Explanation:

Summary:

The data set include two dependent variables which states High School annual earnings and BS annual earnings in the same small firm. Firstly, I used density plot function to view the distribution of two sets of variables. Secondly, I tested the skewness and kurtosis.Skewness of High School is -0.24041 which is left tail. Skewness of BS is 0.53476 which is right tail.Kurtosis of High School is 2.5695 which lower than 3 is platykurtic. Kurtosis of BS is 3.6449 which larger than 3 is leptokurtic. Thirdly, the sample population is 39 for each and has unknow standard deviation, so that I’m going to use t-test to perform the comparing analysis. The result shows p-value which equal to 0.866 is larger than significant value(alpha = 0.05). To the concludsion, there is no difference between yearly earnings of High School and of BS at a small firm.

3 0
3 years ago
programs are often built in a logical sequential order of three connected phases. The three phases in order are__
blsea [12.9K]
The correct answer for this question is IPO or also known as the "Input, Process, Output" Order. This sequential order is a method used by many, especially in terms of Software Engineering. This method is widely use to determine the structure of an informative processing programs and of other process known to programs as well. 
6 0
3 years ago
System software includes all of the following except
Amanda [17]

Answer:

System software includes all of the following except <u>Browsers</u>.

Explanation:

I just know

4 0
3 years ago
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