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4 years ago

Please help me I’m stuck. Will give brainliest!

Mathematics

2 answers:

Fantom [35]4 years ago

7 0

Triangle SET is similar to triangle SAR, so corresponding sides have the same ratio. This means

... ST : SR = ET : AR = 8.19 : 6.37

Then ST : TR = 8.19 : (6.37+8.19) = 8.19 : 14.56

Using division symbols, this is

... ST/TR = 8.19/14.56

Multiplying by TR gives

... ST = TR×(8.19/14.56) = 20.8×8.19/14.56

... ST = 11.7

Anon25 [30]4 years ago

5 0

check the picture below.

so, therefore, the triangles are similar by AA.

now, notice the length RT = 20.8, thus whatever ST might be, RS picks up the slack from the 20.8, namely RS = 20.8 - ST. Then we can use proportions from the corresponding sides.

$\bf \cfrac{ET}{RA}=\cfrac{ST}{RS}\implies \cfrac{8.19}{6.37}=\cfrac{ST}{20.8-ST}\implies \stackrel{\textit{cross-multiplying}}{170.352-8.19ST=6.37ST} \\\\\\ 170.352=6.37ST+8.19ST\implies 170.352=14.56ST \\\\\\ \cfrac{170.352}{14.56}=ST\implies 11.7=ST$

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(10)(11) Geometry Check Ans 10) 5 11) x = 33 y = 38 z = 109

ICE Princess25 [194]

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DaniilM [7]

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where
$(x_{1},y_{1})$ are the coordinates of the first point
$(x_{2},y_{2})$ are the coordinates of the second point
Length of WZ:
We know form our graph that the coordinates of our first point, W, are (1,0) and the coordinates of the second point, Z, are (4,2). Using the distance formula:
$d_{WZ}= \sqrt{(4-1)^2+(2-0)^2}$
$d_{WZ}= \sqrt{(3)^2+(2)^2}$
$d_{WZ}= \sqrt{9+4}$
$d_{WZ}= \sqrt{13}$

We know that all the sides of a rhombus have the same length, so
$d_{YZ}= \sqrt{13}$
$d_{XY}= \sqrt{13}$
$d_{XW}= \sqrt{13}$

Now, we just need to add the four sides to get the perimeter of our rhombus:
$perimeter= \sqrt{13} + \sqrt{13} + \sqrt{13} + \sqrt{13}$
$perimeter=4 \sqrt{13}$
We can conclude that the perimeter of our rhombus is $4 \sqrt{13}$ square units.

2. To solve this, we are going to use the arc length formula: $s=r \alpha$
where
$s$ is the length of the arc.
$r$ is the radius of the circle.
$\alpha$ is the central angle in radians

We know form our problem that the length of arc PQ is $\frac{8}{3} \pi$ inches, so $s=\frac{8}{3} \pi$ , and we can infer from our picture that $r=15$ . Lest replace the values in our formula to find the central angle POQ:
$s=r \alpha$
$\frac{8}{3} \pi=15 \alpha$
$\alpha = \frac{\frac{8}{3} \pi}{15}$
$\alpha = \frac{8}{45} \pi$

Since $\alpha =POQ$ , We can conclude that the measure of the central angle POQ is $\frac{8}{45} \pi$

3. A cross section is the shape you get when you make a cut thought a 3 dimensional figure. A rectangular cross section is a cross section in the shape of a rectangle. To get a rectangular cross section of a particular 3 dimensional figure, you need to cut in an specific way. For example, a rectangular pyramid cut by a plane parallel to its base, will always give us a rectangular cross section.
We can conclude that the draw of our cross section is: