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4 years ago

8

Please anyone help me with this?!

1 answer:

andriy [413]4 years ago

7 0

Answer:

It would be 55.88 but if you round it it would be 55.9 then round it again it would be 56%.

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Simplify the given expression.<br> 2(4 - 2x + y) - 4(5 + x - y)

fiasKO [112]

(8-4x+2y)-(20+4x-4y)
-12-8x+6y or -8x+6y-12

4 0

3 years ago

Please help I have no idea what to do!!

shtirl [24]

A.You have to multiply the Original price(96) by todays discount(1/2)
96×(1/2)=48
Then to find the price 5 days from now you multiply the Original price(96) by the discount 5 days from now(2/3) but this time you subtract what you get from the original price 96×(2/3)=64
96-64=32 or the price of the coat 5 days from now

B. To find how much she would save subtract todays price(48) by the price 5 days from now(32)
48-32=16 She would save 16 dollars

3 0

4 years ago

Read 2 more answers

Which expression is a sum of cubes?

erik [133]

we know that

A polynomial in the form $a^{3} +b^{3}$ is called a sum of cubes

so

Let's verify each case to determine the solution

<u>case A)</u> $-64x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-64=-4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case A) is not a sum of cubes

<u>case B)</u> $-32x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-32=-2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case B) is not a sum of cubes

<u>case C)</u> $32x^{6} y^{12} +125x^{9} y^{3}$

we know that

$32=2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

therefore

the case C) is not a sum of cubes

<u>case A)</u> $64x^{6} y^{12} +125x^{9} y^{3}$

we know that

$64=4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

Substitute

$4^{3}(x^{2})^{3}(y^{4})^{3} +5^{3}(x^{3})^{3}(y)^{3}$

$(4x^{2}y^{4})^{3} +(5x^{3}y)^{3}$

therefore

<u>the answer is</u>

$64x^{6} y^{12} +125x^{9} y^{3}$ is a sum of cubes

6 0

3 years ago

Read 2 more answers

Joe wants to purchase an electric keyboard. The price of the keyboard at Macelli’s, with tax, is $2,344. He can save $150 per mo

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

abought 16 months to buy it and he will have

56 extra cash hope ihelped :3

7 0

4 years ago

Read 2 more answers

Simplify the radical expression

never [62]

Sqrt(56x^2) = x*sqrt(56) = x*sqrt(4*14) = x* sqrt(4) * sqrt(14)

= 2x*sqrt(14) (answer)

3 0

3 years ago