All categories

3 years ago

Please anyone help me with this?!

Mathematics

1 answer:

andriy [413]3 years ago

7 0

Answer:

It would be 55.88 but if you round it it would be 55.9 then round it again it would be 56%.

You might be interested in

I'd sure hope others know how to do this..

ivann1987 [24]

Answer:

omgg they literally deleted 10 x 5

Step-by-step explanation:

it's 50, I'll be the calculator fam

5 0

4 years ago

The drama club was selecting which carnival booths to sponsor at the fall carnival from a list of nine. How many different ways

denis-greek [22]

Answer:

Option B

Step-by-step explanation:

Here we have to apply " combination and permutation. " It is given that the drama club had to choose three booths from a selection of 9, considering the possible ways to choose so. This is a perfect example of combination. In nCr, n corresponds to 9, respectively r corresponds to 3.

$\mathrm{n\:choose\:r},\\nCr=\frac{n!}{r!\left(n-r\right)!},\\\\\frac{9!}{3!\left(9-3\right)!} =\\\frac{9!}{3!\cdot \:6!} =\\\\\frac{9\cdot \:8\cdot \:7}{3!} =\\\frac{504}{6} =\\\\84\\\\Solution = Option B$

Hope that helps!

8 0

3 years ago

PLS HELP a) -3*2-9 b) 2+ -4*-3

alekssr [168]

Answer:

hope this will help you...

Step-by-step explanation:

$a) - 3 \times 2 - 9 \\ solution \\ - 3 \times 2 - 9 \\ - 6 - 9 \\ - 15 \\ \\ b)2 + - 4 \times - 3 \\ solution \\ 2 + - 4 \times - 3 \\ 2 + 12 \\ 14$

7 0

2 years ago

Urgent!

boyakko [2]

Step-by-step explanation:

18.

the last one.

-4.9t² + 24.5t + 117.6 = 0

the ball starts at 117.6 meters height. then, during the first seconds the thrust upwards is adding height, until finally, with more and more seconds passing, gravity will win with a vengeance and pulls the ball down faster and faster than any other force in any other direction.

19.

the general solution for a quadratic equation

y = ax² + bx + c

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = t

a = -4.9

b = 24.5

c = 117.6

t = (-24.5 ± sqrt(600.25 - -4×4.9×117.6))/-9.8 =

= (-24.5 ± sqrt(600.25 + 2304.96))/-9.8 =

= (-24.5 ± sqrt(2905.21))/-9.8 = (-24.5 ± 53.9)/-9.8

t1 = (-24.5 + 53.9)/-9.8 = -3

t2 = (-24.5 - 53.9)/-9.8 = 8

a negative time does not make any sense, so the real solution is : the ball reached the ground after 8 seconds.

20.

now the equation is

-4.9t² + 24.5t + 117.6 = 49

but this is quickly transformed again into a "= 0" equation :

-4.9t² + 24.5t + 68.6 = 0

t = (-24.5 ± sqrt(600.25 - -4×4.9×68.6))/-9.8 =

= (-24.5 ± sqrt(600.25 + 1344.56))/-9.8 =

= (-24.5 ± sqrt(1944.81))/-9.8 = (-24.5 ± 44.1)/-9.8

t1 = (-24.5 + 44.1)/-9.8 = -2

t2 = (-24.5 - 44.1)/-9.8 = 7

again, negative time does not make sense.

the ball will be at 49 m height after 7 seconds.

5 0

2 years ago

Which inequality is represented in the number line below?-5-4-3-2-1 0 1 2 3 4 5OA.-7+2<22+3<4+2OB.-9≤-3x-6≤6OC.-6 ≤ x + 2

S_A_V [24]

The Solution:

The correct answer is [option B]

Given:

Required:

To determine the inequality represented by the given number line.

7 0

1 year ago

Please anyone help me with this?!​

Please anyone help me with this?!