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2 years ago

Witch statement about this equation is true?

Mathematics

2 answers:

Temka [501]2 years ago

5 0

Answer:

B. The equation has one solution

Step-by-step explanation:

Let's get rid of 3x first. We're going to add it to the other side. That way our equation will now look like 3 + 4x = 2. Now subtract the 3 from both sides. SO now you'll be left with 4x = -1. We're are now going to divide by 4 on both sides which will leave us with x = -1/4 or -0.25. The equation has one solution so your answer will be B.

Yuri [45]2 years ago

4 0

The answer is B I believe

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Problem 1.(32 points) A random sample of 100 Uber rides in Chicago has on average 5.4miles per ride. Assume the distribution of

marshall27 [118]

Answer:

a) CI = ( 5,1 ; 5,7 )

b) SE = 0,1

Step-by-step explanation:

a) Sample random n = 100

Mean = μ = 5,4

Standard deviation s = 1,3

CI = 99 % α = 1 % α = 0,01 α/2 = 0,005

z(c) for 0,005 is from z-table z(c) = 2,575

z(c) = ( X - μ ) /s/√n CI = μ ± z(c) * s/√n

CI = 5,4 ± 2,575* 1,3/10

CI = 5,4 ± 0,334

CI = ( 5,1 ; 5,7 )

b) SE = Standard deviation / √n

SE = 1,3 /10 SE = 0,1

We can support that with 99 % of probability our random variable will be in the CI.

6 0

2 years ago

Diane's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Diane

Shalnov [3]

4.05x+5.25(149-x)=710.25
Solve for x
X=60 ........4.05

149-60=89.....5.25

5 0

3 years ago

A school creates a histogram representing the individual travel times for students riding the bus to school. The histogram is ri

aliya0001 [1]

THIS IS THE COMPLETE QUESTION;

A school creates a histogram representing the individual travel times for students riding the bus to school. The histogram is right-skewed, and the mean time is 25 minutes.

Which statement best describes the possible value of the median time of students riding the bus to school?

The median time is less than 25 minutes.

The median time is exactly equal to 25 minutes.

The median time is approximately equal to 25 minutes.

The median time is greater than 25 minutes.

Answer;

The median time is less than 25 minutes

Step-by-step explanation

✓When the histogram is skewed right, it implies that the mean is greater than the median which means The median time is less than the mean.

This is as a result of few large values that drive as a result of skewed-right data

✓Skewness can be explained as measure of the asymmetry of a histogram When a histogram is symmetrical when it has a normal distribution, i.e when the same amount of data falls on both sides of the mean. Ahistogram has a normal distribution will have a skewness of 0.

✓the skewness can be explained in terms positive/right relationship:

√nonparametric skew implies that the mean is greater than the median, which means it is at the the right.

√A negative/left nonparametric skew can be explained as when the mean is < the median. I e it fall to the left .

Therefore, the median is less than 25 minutes

7 0

3 years ago

Read 2 more answers

Sameen bought 2 1/5 pounds of carrots for $6.60. At that rate, how much would 1 pound of carrots cost?

Vanyuwa [196]

Answer:

Step-by-step explanation:

4 0

2 years ago

Show that the line integral is independent of path by finding a function f such that ?f = f. c 2xe?ydx (2y ? x2e?ydy, c is any p

Juli2301 [7.4K]

I'm reading this as

$\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy$

with $\nabla f=(2xe^{-y},2y-x^2e^{-y})$ .

The value of the integral will be independent of the path if we can find a function $f(x,y)$ that satisfies the gradient equation above.

You have

$\begin{cases}\dfrac{\partial f}{\partial x}=2xe^{-y}\\\\\dfrac{\partial f}{\partial y}=2y-x^2e^{-y}\end{cases}$

Integrate $\dfrac{\partial f}{\partial x}$ with respect to $x$ . You get

$\displaystyle\int\dfrac{\partial f}{\partial x}\,\mathrm dx=\int2xe^{-y}\,\mathrm dx$
$f=x^2e^{-y}+g(y)$

Differentiate with respect to $y$ . You get

$\dfrac{\partial f}{\partial y}=\dfrac{\partial}{\partial y}[x^2e^{-y}+g(y)]$
$2y-x^2e^{-y}=-x^2e^{-y}+g'(y)$
$2y=g'(y)$

Integrate both sides with respect to $y$ to arrive at

$\displaystyle\int2y\,\mathrm dy=\int g'(y)\,\mathrm dy$
$y^2=g(y)+C$
$g(y)=y^2+C$

So you have

$f(x,y)=x^2e^{-y}+y^2+C$

The gradient is continuous for all $x,y$ , so the fundamental theorem of calculus applies, and so the value of the integral, regardless of the path taken, is

$\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy=f(4,1)-f(1,0)=\frac9e$

8 0

3 years ago