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3 years ago

What are the leading coefficient and degree of the polynomial? 20-w^9+2w^3+12w

Mathematics

1 answer:

Ilya [14]3 years ago

6 0

I assume you want the leading coefficient because there is only 1.

The leading coefficient is always in front of the term with the greatest exponent.

Leading coefficient = -1.

The degree of this function is 9. It is a ninth degree polynomial function. Why 9? It is a 9th degree polynomial because 9 is the greatest power.

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Help me please idk how to do it

frozen [14]

You do £68.85 - £15.30= (the answer)
Then you do the answer of that divided by 0.85

5 0

3 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

3 years ago

Convert -√3-i to polar form.

Jlenok [28]

Answer:

-sqrt(3) -i = 2 cis (7pi/6)

Step-by-step explanation:

-sqrt(3) -i

We can find the radius

r = sqrt( (-sqrt(3)) ^2 + (-1) ^2)

= sqrt( 3 + 1)

= sqrt(4)

= 2

theta = arctan (y/x)

arctan (-1/-sqrt(3))

arctan (1/sqrt(3))

theta = pi/6

But this is in the first quadrant, and we need it in the third quadrant

Add pi to move it to the third quadrant

theta = pi/6 + 6pi/6

=7pi/6

-sqrt(3) -i = 2 cis (7pi/6)

6 0

3 years ago

Read 2 more answers

Solve for r. 17.4=3r. R=?

Bumek [7]

Answer:

r=5.8

Step-by-step explanation:

Just do 17.4 divided by 3

And you get R

Hope this helps!

6 0

3 years ago

Help! <br> Expressions and equations

Dovator [93]

Answer:

1. 16−6=10

2. 4⋅2+1

3. x÷25

4. y+8=40

Explanation:

This is an equation—two expressions are connected with an .This is an expression—no equal sign. This is an expression—no equal sign. This is an equation—two expressions are connected with an equal sign.

5 0

3 years ago