Question

The sum of 5 consecutive integers is 110.

Answer 1

They would be 20, 21, 22, 23, and 24

Answer 2

To find the first integer, let's represent the integers with variable x
x+(x+1)+(x+2)+(x+3)+(x+4)=110                x+1=20+1=21
5x+10=110                                               x+2=20+2=22
5x+10-10=110-10                                     x+3=20+3=23
5x=100                                                   x+4=20+4=24
5x/5=100/5                         
x=20                                   20+21+22+23+24=110