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Alex787 [66]
3 years ago
5

A circle has a radius of 15 inches. What is the area, in square inches, of this circle? (The area of a circle with a radius of r

is equal to π r 2 .)
Mathematics
1 answer:
Natali [406]3 years ago
4 0

Answer:

225\pi

Step-by-step explanation:

15×15=225=r^2

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Hello there, <br><br> can someone please help me with this question
monitta

Answer:

10 sides.

Step-by-step explanation:

Two same interior angles + 72 degrees = 360.

Thus, the interior angle of the polygon is \frac{360-72}{2} =144.

The formula to find the interior angle of a polygon is \frac{180(n-2)}{n}

\frac{180(n-2)}{n} =144

Multiply both sides by n:

\frac{180\left(n-2\right)}{n}n=144n

180\left(n-2\right)=144n

Expand:

180n-360=144n

Add 360 to both sides:

180n-360+360=144n+360

180n=144n+360

Subtract 144n from both sides:

180n-144n=144n+360-144n

36n=360

Divide both sides by 36:

\frac{36n}{36}=\frac{360}{36}

n=10

7 0
2 years ago
What is the perimeter and area of the figure?
Rudiy27

Perimeter is the sum of all outside dimensions:

5 + 3 + 1 + 2 + 4 + 5 = 20cm

Area = (5 x 5) - (2*1) = 25 - 2 = 23 cm^2

7 0
3 years ago
3 more than 6 times a number
Snowcat [4.5K]

Answer:

assuming you're looking for an expression, it would be written as "6x+3".

4 0
3 years ago
Read 2 more answers
Please help Evaluate the expression. (7 – 4)[(5 +
IgorLugansk [536]
You have to subtract 4 from 7 and then add 5 and 3 then add 8 and 2 then multiply 10 with 3 to get 30. 
8 0
3 years ago
What is greater one seventh or one nineth
Anton [14]

Method 1:

Look at the picture.

\dfrac{1}{7} is greater than \dfrac{1}{9}

\boxed{\dfrac{1}{7}>\dfrac{1}{9}}

Method 2:

Find the common denominator:

multiples of 7: 0, 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, ...

multiples of 9: 0, 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, ...

63 = 7 · 9

\dfrac{1}{7}=\dfrac{1\cdot9}{7\cdot9}=\dfrac{9}{63}\\\\\dfrac{1}{9}=\dfrac{1\cdot7}{9\cdot7}=\dfrac{7}{63}

\dfrac{9}{63} > \dfrac{7}{63}

therefore

\dfrac{1}{7} > \dfrac{1}{9}

3 0
3 years ago
Read 2 more answers
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