Answer:
a. 2401.06
b. 37.54%
c. 56.3%
Step-by-step explanation:
hopefully this is right
*note: I think you forgot to convert 4-2 back into yards.
a. Robbie's field of view to the North end includes parts not on the football field. so to find the area of the football field he can see, we need to find:
total area of what Robbie sees - area of non football field Robbie sees
what you shaded represents the total of what Robbie sees. it's a triangle. area of a triangle is 1/2(b)(h) where h is distance away and b is width of view.
total area = 1/2(170)(30.92) = 2628.56 yd
area of non football field (pipe to South end)
= 1/2(50)(9.1) = 227.5
so 2628.56 - 227.5 = 2401.06
b. area found in part a / total area of football field
2401.06 / (120*53.3) = .3754
.3754 * 100 = 37.54%
c. the chance of Robbie seeing the touchdown depends on how much of the (North) endzone he can see.
area of north endzone is
10 * 53.3 = 533.
area Robbie sees in endzone is
2628.56 - 2328.48 = 300.08
(found by total area Robbie sees - area of non endzone Robbie sees)
300.08 / 533 = 0.563
= 56.3%
(a4-6a+5)-(a4-3a+4a-6)
by expressing like term
a4-a4=0
-6a-(-3a+4a)=-5a
5-(-6)=11
:we have-5a+11
You formatted the equation wrong for the setting your calculus on i would recommend using a Ti-34
The 2 lengths + 2 widths of the rectangle will equal 160 meters
So, for example, length = 50 m and width = 30m would fit the bill
2*50 + 2*30 = 160 m
