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Doss [256]
2 years ago
13

Pls help with these questions!!!

Mathematics
1 answer:
DedPeter [7]2 years ago
6 0

Answer:

9 \times 9 - 3 = 81 - 3 = 78

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What is the value of z if z/4 = 12
Digiron [165]

Answer:

z = 48 :)

Step-by-step explanation:

z ÷ 4 = 12

So, all you need to do is multiply 12 by four, to get z- 48

hope this helped!

5 0
3 years ago
Read 2 more answers
Point w id located at (-2,3) on a coordinate plane. Point W is reflected over the x-axis to create point W" is then reflected ov
Anna11 [10]

Answer:

W'' = (2, -3)

Step-by-step explanation:

Reflection over the x-axis negates the y-coordinate and leaves the x-coordinate alone. The W becomes ...

... W' = (-2, -3)

Reflection over the y-axis negates the x-coordinate and leaves the y-coordinate alone. The W' becomes ...

... W'' = (2, -3)

5 0
2 years ago
Read 2 more answers
Math question<br> i kind of need this done quicker, however no rush..! :)<br><br> x=-2y<br> x-y=9
strojnjashka [21]

Answer:

(6,-3) or x=6 y= -3

Step-by-step explanation:

8 0
3 years ago
determine whether the equation represents a direct varation. if it does, find the constant, find the constant variation. 2y = 5x
SVETLANKA909090 [29]
Is it 5x1?
or 5x+1   cause i'm confused 
6 0
3 years ago
Cubed root x cubed root x2​
Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

7 0
3 years ago
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