Question

Could someone explain/answer these?

Answer 1

1)

f(x) = x² + 9                 g(x) = 24 + 4x

f(4) = (4)² + 9               g(-1) = 24 + 4(-1)

     = 16 + 9                         = 24 - 4

    =  25                              = 20

$\frac{f(4)}{g(-1)} = \frac{25}{20} = \frac{125}{100} = 1.25$

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g(x) = 2ˣ - 4                            f(x) = 4x² - 5x - 5

g(6) = 2⁶ - 4                          f(-5) = 4(-5)² - 5(-5) - 5

     = 64 - 4                                  = 100 + 25 - 5

     = 60                                       = 120

$\frac{g(6)}{f(-5)} = \frac{60}{120} = \frac{1}{2} = 0.5$

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f(x) = (3x + 7)²

f(1) = (3(1) + 7)²

    = (3 + 7)²

    = (10)²

    = 100

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3xy + 2x² - y³  ; when x = 6 and y = -2

3(6)(-2) + 2(6)² - (-2)³

 -36     +  72   -  (-8)

           36        +  8

                  44

Answer 2

When it asks for the value of f(?) or g(?), you plug whatever number is in the parentheses into the “x” of the equation that contains f or g. Hope this helped