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3 years ago

THE LA THEOREM IS THE SPECIAL CASE OF THE ?

Mathematics

2 answers:

Andru [333]3 years ago

8 0

AAS theorem and ASA postulate.

True [87]3 years ago

7 0

Answer:

AAS theorem and ASA postulate

Step-by-step explanation:

apex

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Please huryyyyyyyyyyy!!!!!!!!!!!!!

bearhunter [10]

Answer:

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Step-by-step explanation:

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1 year ago

Find the degree of the minomial. 6xy

EastWind [94]

Count up the exponents.

6xy

Both 'x' and 'y' have exponents of 1.

1 + 1 = 2

So this is a 2nd degree monomial.

4 0

2 years ago

Read 2 more answers

I need help solving for X

8_murik_8 [283]

Answer:

x = 63

Step-by-step explanation:

This is a right angle, and we know that there are 90 total degrees in a right angle. Because of this information, we know that the degrees of both angles, added together, should come out to 90. This reasoning looks like this:

$25+(x+2)=90$

Now, it's much easier to solve for x. I'll start by removing the parentheses and combining like terms.

$25+x+2=90\\25+2+x=90\\27+x=90$

Now, let's remove 27 both sides to isolate x and figure out what it's equal to.

$27+x=90\\x = 63$

So, the measure of x is 63 degrees. We can make sure this is correct by using our equation:

Is $25+(63+2)=90$ ? Yes, because 63 + 2 is equal to 65, and 65 plus 25 is equal to 90. So our answer is correct.

If you need any more help, let me know! :)

6 0

2 years ago

Read 2 more answers

Evaluate -3 3 -27 -9 9 27

s2008m [1.1K]

I believe the answer is -27

4 0

3 years ago

Read 2 more answers

-3|9x-7|=2 Find the answer for x

labwork [276]

<h2>Solving Equations with Absolute Expressions</h2><h3>Answer:</h3>

No Solutions

<h3>Step-by-step explanation:</h3>

Given:

$-3|9x -7| = 2$

Rewriting the given equation:

$-3|9x -7| = 2 \\ |9x -7| = -\frac{2}{3}$

We have to realize that the right side of the equation, $|9x -7|$ , will always be positive no matter what real values of $x$ (because we're taking the absolute value of the expression) and we are equating it to a negative constant number, $-\frac{2}{3}\\$ . Something that is always positive will never be negative so there's no value for $x$ that satisfies the solution.

$\rule{6.5cm}{0.5pt}$

You may not read the following passage that I have written.

$\rule{6.5cm}{0.5pt}$

Solving by positive of the expression:

$9x -7 = -\frac{2}{3} \\ 9x = -\frac{2}{3} +7 \\ 9x = -\frac{2}{3} +\frac{21}{3} \\ 9x = \frac{19}{3} \\ 9x \times \frac{1}{9} = \frac{19}{3} \times \frac{1}{9} \\ x = \frac{19}{27}$

Solving by the negative of the expression:

$-(9x -7)= -\frac{2}{3} \\ 9x -7 = \frac{2}{3} \\ 9x = \frac{2}{3} +7 \\ 9x = \frac{2}{3} +\frac{21}{3} \\ 9x = \frac{23}{3} \\ 9x \times \frac{1}{9} = \frac{23}{3} \times \frac{1}{9} \\ x = \frac{23}{27}$

Checking: $x = \frac{19}{27}\\$

$-3|9(\frac{19}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|-\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2$

$x = \frac{19}{27}\\$ is an extraneous solution.

Checking: $x = \frac{23}{27}\\$

$-3|9(\frac{23}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2$

$x = \frac{23}{27}\\$ is an extraneous solution.

8 0

2 years ago