Plzz help! Part A: If (7^2)^x = 1, what is the value of x? Explain your answer.

Mathematics

1 answer:

BigorU [14]3 years ago

4 0

$(7^2)^x=1\\
49^x=1\\
x=0\\\\
(7^0)^x=1\\
1^x=1\\
x\in\mathbb{R}$

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the third term of an arithmetic sequence is 24 and the fifth is 32 if the first term is a1. which is an equation nth term of the

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An = a1 + (n - 1)(d)
Where a1 is the first term and d is the common difference.
First find d, the common difference.
24, ____, 32
a3 a4 a5
Subtract 32-24 = 8
Subtract a5 - a3 = 2
Divide 8/2 = 4
d = 4
Use d and one of the values they give us to find a1.
a3 = 24
24 = a1 + (3 - 1)(4)
24 = a1 + 2(4)
24 = a1 + 8
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16 = a1
an = 16 + (n - 1)(4)
Can also be written
an = 16 + 4n - 4
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8 0

3 years ago

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What is the simplified form of this expression 7(^3sqrt2x)-3(^3sqrt16x)-3(^3sqrt8x)

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Answer:

Solution,

$7( \sqrt[3]{2x} ) - 3( \sqrt[3]{16x} ) - 3( \sqrt[3]{8x} ) \\ = 7 \sqrt[3]{2x} - 3 \times ( \sqrt[3]{2 \times 2 \times 2 \times 2x} - 3 \times \sqrt[3]{2 \times 2 \times 2x} \\ = 7 \sqrt[3]{2x} - 3 \times (2 \sqrt[3]{2} x) - 3 \times 2x \\ = 7 \sqrt[3]{2x} - 3 \times 2 \times \sqrt[3]{2x} - 3 \times 2x \\ = 7 \sqrt[3]{2x} - 6 \sqrt[3]{2x} - 6x$