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krek1111 [17]
3 years ago
14

Patti has two glue sticks that are partially used. One has 1/5 left, and one has 3/10 left. Which glue stick has more glue?

Mathematics
2 answers:
marishachu [46]3 years ago
8 0

Answer:

the one with 3/10 left has more

Step-by-step explanation:

because 1/5 is equal to 2/10 and 3/10>2/10

prisoha [69]3 years ago
7 0

Answer:

The one with the 3/10 of glue left

Step-by-step explanation:

So, first you would want to change the 1/5's denominator to the same denominator as the 3/10's, because we want to compare the two.

- First, you would need to find the common denominator.

The common denominator for 5 and 10 is ten, so we don't need to times anything to 10, but we need to times 1/5 by 2.

1/5* 2/2= 2/10

Now that it is done, we compare the two.

Which one is larger, 2/10 or 3/10?

3/10 is greater, so we put down the 3/10 of glue left.

Hope this helped!

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PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy

Now evaluate,

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Now integrate this w.r.t. y:

\int_{-6}^{6}\frac{5}{6}dy = 10

So,

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10

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lozanna [386]

Answer: -4


Step-by-step explanation:


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vfiekz [6]

Answer:

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Step-by-step explanation:

Given:

Height of cylinder (h) = 10 yd

Diameter of cylinder (d) = 14 yd

We need to find the surface area of the cylinder.

Solution:

First we will find the radius of the cylinder.

Radius is half of the diameter.

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Now we know that;

Surface area of cylinder is equal to 2 times π times radius(r) times sum of radius (r) and height (h).

Framing in equation form we get;

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Substituting the given values we get;

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sleet_krkn [62]
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