Answer:
The range of weights of the middle 99.7% of M&M’s is between 0.8187 and 1.0203.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
Sample mean:
Sample standard deviation:
What is the range of weights of the middle 99.7% of M&M’s?
By the Empirical Rule, within 3 standard deviations of the mean, so:
0.9195 - 3*0.0336 = 0.8187.
0.9195 + 3*0.0336 = 1.0203.
The range of weights of the middle 99.7% of M&M’s is between 0.8187 and 1.0203.
Total area of the circle is 1.12π square inches.
<h3>What is Area of circle?</h3>
The Area of circle is π times the square of the radius.
i.e., A = πr²
Given:
Area of one circle = 0.56π
As the second circle is also identical then the area will be same.
So, the total area of circle is
=2* 0.56π
=1.12π square inches.
Learn more about area of circle here:
brainly.com/question/27950508
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Answer:
Step-by-step explanation:
The generating function a(x) produces a power series ...
where the coefficients are the elements of the given sequence.
We observe that the given sequence has the recurrence relation ...
This can be rearranged to ...
We can formulate this in terms of a(x) as follows, then solve for a(x).
The generating function is ...
a(x) = 1/(1+2x)
Answer is x=2 bacause u just jave to listen. this is the equation . 3x+4=5x-2. solve
Since it asks you to estimate, you would round the 4.6 up to 5. The estimate volume would be 125 inches^3; answer C.
