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Anestetic [448]
2 years ago
11

Write the equation of a line, in Point slope form that passes through (5,6) and has a slope of -3​

Mathematics
1 answer:
Mademuasel [1]2 years ago
7 0

Answer:

y = -3x + 21

Step-by-step explanation:

(5,6)

y = mx + b

6 = -3 × 5 + b

solving for b

b = 6 - (-3)(5)

b = 21

Therefore,

y = -3x + 21

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For what value(s) of k will the relation not be a function
skelet666 [1.2K]

We are given two relations

(a)

Relation (R)

R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

k-8.3+2.4k=-\frac{3}{4} k

3.4k-8.3=-\frac{3}{4}k

3.4k\cdot \:10-8.3\cdot \:10=-\frac{3}{4}k\cdot \:10

4k-83=-\frac{15}{2}k

34k=-\frac{15}{2}k+83

\frac{83}{2}k=83

83k=166

k=2............Answer

(b)

S = {(2−|k+1| , 4), (−6, 7)}

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

2-|k+1|=-6

2-\left|k+1\right|-2=-6-2

-\left|k+1\right|=-8

\left|k+1\right|=8

Since, this is absolute function

so, we can break it into two parts

|f\left(k\right)|=a\quad \Rightarrow \:f\left(k\right)=-a\quad \mathrm{or}\quad \:f\left(k\right)=a

k+1=-8\quad \quad \mathrm{or}\quad \:\quad \:k+1=8

we get

k+1=-8\quad

k=-9

k+1=8\quad

k=7

so,

k=-9\quad \mathrm{or}\quad \:k=7...............Answer

5 0
3 years ago
Can someone pleaseeeeee help on either question pleaseeeee 100000000 points
SIZIF [17.4K]
Number 3 is gonna be 2 and Number 4 will be 294 I hope this would help u a little bit I will figure out the Other questions



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Answer:

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