1/2 because 7/6 & 4/3 are improper fractions(fractions that have a higher numerator than a denominator) and 3/3 should just be written as 1.
Answer:
Step-by-step explanation:
A quadratic equation is given to us and we need to solve the equation using the quadratic formula . The given equation is ,
Open the brackets in RHS ,
Transpose all the terms to LHS ,
The general form of a quadratic equation is ax² + bx + c = 0 , and the roots of the equation by the Quadratic Formula ( Shreedhacharya's Formula ) is given by ,
Using the quadratic formula , we have ,
Simplify ,
The cut-off point is 0.5: higher than this would be closer to 1, and lower would be closer to 0
and 3/8 is lower than 0.5: we know this because a bigger number, 4/8 is equal to 0.5
so it's closer to 0!
Answer:
x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4
Step-by-step explanation:
Solve for x:
2 x^2 - 5 x + 5 = 0
Hint: | Using the quadratic formula, solve for x.
x = (5 ± sqrt((-5)^2 - 4×2×5))/(2×2) = (5 ± sqrt(25 - 40))/4 = (5 ± sqrt(-15))/4:
x = (5 + sqrt(-15))/4 or x = (5 - sqrt(-15))/4
Hint: | Express sqrt(-15) in terms of i.
sqrt(-15) = sqrt(-1) sqrt(15) = i sqrt(15):
Answer: x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4
