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ikadub [295]
3 years ago
6

Which of these problem types can not be solved using the Law of Sines?

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
5 0
A. sss because we need an angle to solve using law of sines
Triss [41]3 years ago
5 0

Answer: The correct option are A, B and D.

Explanation:

The law of sine states that,

\frac{\sin A}{a} =\frac{\sin B}{b}=\frac{\sin C}{c}

Where A, B, C are interior angles of the triangle and a, b, c are sides opposite these angles respectively as shown in below figure.

Since we need the combination of two angles and one side or two sides and one angle.

The Law of sine is useful for AAS and SSA type problems.

Reason for correct option:

In  option A three sides are known but no angle is not given, therefore the SSS problem can not be solved by Law of sine and the option A is correct.

In option B a side is known and two inclined angle on that line are known. But to use Law of sine we want the line and angle which in not inclined on that line, therefore the ASA problem can not be solved by Law of sine and the option B is correct.

In option D two sides and their inclined angle is known. But to use Law of sine we want the side and angle which in not inclined on that line, therefore the SAS problem can not be solved by Law of sine and the option D is correct.

Reason for incorrect option:

In option C, the two consecutive angles are given and a side which makes the second angle with base side, therefore the first angle is opposite to the given side, so the law of sine can be used for AAS problems.

Therefore, option C is incorrect.

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Hi, can you help me answer this question please, thank you!
pychu [463]

Okay, here we have this:

4 0
1 year ago
How many Positive Integers are there between 20 to 100 exclusively?
maksim [4K]

Answer:

79

Step-by-step explanation:

There is a cool easy way to solve this kind of problem. If a range is given, and the entire range increases in incrememnts of 1, then you can find the number intergers inclusive by taking the first number and subtracting it from the last and adding 1. Since in this problem you want it exclusive, we can rewrite the range to 21-99.

99-21 +1 = 78 + 1 = 79

7 0
3 years ago
A group of children, adults, and senior citizens attended three different art exhibits that have different ticket prices for eac
jok3333 [9.3K]

Answer:

Option D) c = 100, a = 50, s = 20

Step-by-step explanation:

we have

6c + 7a + 2s = 990  -----> equation A

3c + 3a + 4s = 430  -----> equation B

2c + 4a + 4s = 480 ----> equation C

Isolate variable s in equation A

2s = 990 -6c-7a  

s=495-3c-3.5a -----> equation D

Substitute equation D in equation B and in equation C

3c + 3a + 4(495-3c-3.5a) = 430

3c + 3a +1,980-12c-14a= 430

-9c-11a=-1,550 -----> equation E

2c + 4a + 4(495-3c-3.5a) = 480

2c+4a+1,980-12c-14a=480

-10c-10a=-1,500 -----> 10c+10a=1,500 -----> equation F

Solve the system of equations E and F by graphing

using a graphing tool

Let

The variable c -----> the x-axis

The variable a ----> the y-axis

The solution is the point (50,100)

see the attached figure

so

c=50, a=100  

Find the value of s

s=495-3(50)-3.5(100)=-5 -----> is not make sense

therefore

Let

The variable c -----> the y-axis

The variable a ----> the x-axis

The solution is the point (50,100)

so

a=50, c=100  

Find the value of s

s=495-3(100)-3.5(50)=20

therefore

The solution is

c=100,a=50,s=20

7 0
4 years ago
Jed has 25 toy cars. Kai has 32 toy cars. Ken has fewer cars than either jed or kai. How many cars might Ken have?
Fiesta28 [93]

Answer:

If k is an integer, the number of toy cars Ken might have can be expressed as the interval

0 ≤ k < 25

3 0
3 years ago
Write an equation in slope-intercept form of the line with the given parametric equations.
Montano1993 [528]

Answer:

y = \frac{9}{8}\cdot x -\frac{3}{8}

Step-by-step explanation:

The parametric equations are described below:

x = 8\cdot t + 3 and y = 9\cdot t + 3

The slope-intercept equation is constructed by eliminating t from both formulae:

t = \frac{x-3}{8} and t = \frac{y-3}{9}

\frac{x-3}{8} = \frac{y-3}{9}

9\cdot (x-3) = 8\cdot (y-3)

9\cdot x - 27 = 8\cdot y -24

9\cdot x -3 = 8\cdot y

y = \frac{9}{8}\cdot x -\frac{3}{8}

6 0
3 years ago
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