Answer:
y = 3 cos(π/5 x) + 5
Step-by-step explanation:
The amplitude is half the difference of the min and max.
A = (8 − 2) / 2
A = 3
The midline is the average of the min and max.
C = (8 + 2) / 2
C = 5
The difference in the x values of the min and max is half the period.
T/2 = 5 − 0
T = 10
The function is a maximum at x = 0, so use cosine.
y = 3 cos(2π/10 x) + 5
y = 3 cos(π/5 x) + 5
Sin(x) = cos(90-x) , so the answer is 0.83 * 0.55
This is not an equation so it cannot be solved.
Add 2 more because if Pete has 5 and Jay has 2 more that should give a signal to add
Answer:
d = ≈ 5.1 ( to 1 dec. place )
Step-by-step explanation:
to calculate the distance d use the distance formula
d = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (, 3) and (x₂, y₂ ) = (, 8)
d =√ ( - )² - (8 - 3)²
= = ≈ 5.1