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erica [24]
3 years ago
6

Each limit represents the derivative of some function f at some number a. State such an f and a in each case.

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0

Answer:

<h2>a = 0</h2><h2>f(h) = \frac{\sqrt{9+h} - 3}{h}</h2><h2>limit of the function is 1/6</h2>

Step-by-step explanation:

The general form representing limit of a function is expressed as shown below;

\lim_{h \to a} f(h) where a is the value that h will take and use in the function f(h). It can be expressed in words as limit of function f as h tends to a. Comparing the genaral form of the limit to the limit given in question \lim_{h \to 0} \frac{\sqrt{9+h} - 3}{h}, it can be seen that a = 0 and f(h) = \frac{\sqrt{9+h} - 3}{h}

Taking the limit of the function

\lim_{h \to 0} \frac{\sqrt{9+h} -3}{h}\\= \frac{\sqrt{9+0}-3 }{0}\\= \frac{0}{0}(indeterminate)

Applying l'hopital rule

\lim_{h \to 0} \frac{\frac{d}{dh} (\sqrt{9+h} - 3)} {\frac{d}{dh} (h)}\\= \lim_{h \to 0}  \frac{1}{2}  (9+h)^{-1/2} /1\\=\frac{1}{2}  (9+0)^{-1/2}\\= \frac{1}{2}  * \frac{1}{\sqrt{9}  } \\= 1/2 * 1/3\\= 1/6

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