The common factor is 7 so its
7(2x - 3)
Answer:
From the chapter Playing with numbers
we can define derek has 2×10^2 + 7 × 10^1 + 7× +0^0
as If ABC a number then ABC can be written as 10^2A+10^1B+10^0C
Hope it helps
Answer:
132 ribbons
Step-by-step explanation:
33/1 = 1/4
33 × 4 = 132
Given :
C, D, and E are col-linear, CE = 15.8 centimetres, and DE= 3.5 centimetres.
To Find :
Two possible lengths for CD.
Solution :
Their are two cases :
1)
When D is in between C and E .
. . .
C D E
Here, CD = CE - DE
CD = 15.8 - 3.5 cm
CD = 12.3 cm
2)
When E is in between D and C.
. . .
D E C
Here, CD = CE + DE
CD = 15.8 + 3.5 cm
CD = 19.3 cm
Hence, this is the required solution.
