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2 years ago

What would be the next step?

Mathematics

2 answers:

levacccp [35]2 years ago

7 0

The next step is to ADD 10x to both sides!

Leya [2.2K]2 years ago

5 0

Answer:

11-5=-4x+10x

6=6x

6/6=x

X=1

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A 1year loan at 6% ended up costing $144 in simple interest . How much money was borrowed

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<span>How much money was borrowed</span> $144/0.06 = $2,400.

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2 years ago

What is x divided by 2?

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X/2 is the same thing as 1/2x

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3 years ago

The quotient of a number 2, minus 9, is 14

rodikova [14]

I think your answer is going to be 23

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3 years ago

4. What is the solution of the system of equations?<br> y=-2x+5<br> y=-2x+20

Norma-Jean [14]

The system of equation, y = -2x + 5 and y = -2x + 20, have no solution.

<h3>How to Find the Solution of a System of Equations?</h3>

The solution to a system of equations is the ordered pair of x and y that makes both equations true.

Given the system of equations,

y = -2x + 5 --> equation 1

y = -2x + 20 --> equation 2

Subtract to eliminate variable "y"

0 = 0 + 25

0 = 25 [this is not true]

Therefore, no solution exist for the system of equations.

Thus, we can conclude that, the system of equation, y = -2x + 5 and y = -2x + 20, have no solution.

Learn more about system of equations on:

brainly.com/question/14323743

#SPJ1

3 0

1 year ago

The 2008 Workplace Productivity Survey, commissioned by LexisNexis and prepared by WorldOne Research, included the question, "Ho

vitfil [10]

Answer:

Therefore, the sampling distribution of $\bar{x}$ is normal with a mean equal to 9 hours and a standard deviation of 0.7969 hours.

The 95% interval estimate of the population mean $\mu$ is

LCL = 7.431 hours to UCL = 10.569 hours

Step-by-step explanation:

Let X be the number of hours a legal professional works on a typical workday. Imagine that X is normally distributed with a known standard deviation of 12.6.

The population standard deviation is

$\sigma = 12.6 \: hours$

A sample of 250 legal professionals was surveyed, and the sample's mean response was 9 hours.

The sample size is

$n = 250$

The sample mean is

$\bar{x} = 9 \: hours$

Since the sample size is quite large then according to the central limit theorem, the sample mean is approximately normally distributed.

The population mean would be the same as the sample mean that is

$\mu = \bar{x} = 9 \: hours$

The sample standard deviation would be

$s = {\frac{\sigma}{\sqrt{n} }$

Where is the population standard deviation and n is the sample size.

$s = {\frac{12.6}{\sqrt{250} }$

$s = 0.7969 \: hours$

Therefore, the sampling distribution of $\bar{x}$ is normal with a mean equal to 9 hours and a standard deviation of 0.7969 hours.

The population mean confidence interval is given by

$\text {confidence interval} = \mu \pm MoE\\\\$

Where the margin of error is given by

$$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sampling size, s is the sample standard deviation and is the t-score corresponding to a 95% confidence level.

The t-score corresponding to a 95% confidence level is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 250 - 1 = 249

From the t-table at α = 0.025 and DoF = 249

t-score = 1.9695

$MoE = t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) \\\\MoE = 1.9695\cdot \frac{12.6}{\sqrt{250} } \\\\MoE = 1.9695\cdot 0.7969\\\\MoE = 1.569\\\\$

So the required 95% confidence interval is

$\text {confidence interval} = \mu \pm MoE\\\\\text {confidence interval} = 9 \pm 1.569\\\\\text {LCI } = 9 - 1.569 = 7.431\\\\\text {UCI } = 9 + 1.569 = 10.569$

The 95% interval estimate of the population mean $\mu$ is

LCL = 7.431 hours to UCL = 10.569 hours

8 0

3 years ago