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4 years ago

I dont understand this question, and needs to be done by tomorrow morning please help

Mathematics

1 answer:

gladu [14]4 years ago

3 0

Answer:

ABCD and EFGH

ABCD and PQRS (or EFGH and PQRS)

Dilate by a scale factor of 3

Step-by-step explanation:

Congruent means they have the same shape and size.

Similar means they have the same shape, but not necessarily the same size.

The orientation (rotation angle) or position do not matter.

EFGH is reflected and rotated, so it maintains the same shape and size as ABCD. Therefore, they are congruent.

PQRS is scaled and translated, so it has the same shape, but different size than ABCD. Therefore, they are similar but not congruent.

Also, PQRS is similar to EFGH, but not congruent.

To make EFGH congruent to PQRS, we need to make it the same size. So we need to scale EFGH by a factor of 3.

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grigory [225]

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3 years ago

A train travels at an average speed of 18 m/s.

GrogVix [38]

Answer:

28 seconds

Step-by-step explanation:

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4 years ago

What is the solution to the following system of equations?

deff fn [24]

Answer:

D) x=-3, y=-7

Step-by-step explanation:

9x - 7y = 22

x + 3y= -24

9x - 7y = 22

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x= -24-3y

-216-27y-7y=22

x= -24-3y

-34y=22+216

x= -24-3y

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x= -24-3y

y=238/(-34)

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y=-7

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7 0

3 years ago

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

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3 years ago

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Step-by-step explanation:

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4 years ago

I dont understand this question, and needs to be done by tomorrow morning please help​

I dont understand this question, and needs to be done by tomorrow morning please help