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Dovator [93]
3 years ago
9

I dont understand this question, and needs to be done by tomorrow morning please help​

Mathematics
1 answer:
gladu [14]3 years ago
3 0

Answer:

ABCD and EFGH

ABCD and PQRS (or EFGH and PQRS)

Dilate by a scale factor of 3

Step-by-step explanation:

Congruent means they have the same shape and size.

Similar means they have the same shape, but not necessarily the same size.

The orientation (rotation angle) or position do not matter.

EFGH is reflected and rotated, so it maintains the same shape and size as ABCD.  Therefore, they are congruent.

PQRS is scaled and translated, so it has the same shape, but different size than ABCD.  Therefore, they are similar but not congruent.

Also, PQRS is similar to EFGH, but not congruent.

To make EFGH congruent to PQRS, we need to make it the same size.  So we need to scale EFGH by a factor of 3.

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Rafel counted a total of 40 white cars and yellow cars.there were 9 times as many white cars as yellow cars. how many white cars
Degger [83]
Let w bet the number of white cars and y the numbers of yellow cars.
"Rafael counted a total of 40 white and yellow cars" So w+y = 40.
"There were 9 times as many white cars as yellow cars" So 9Y = W

We get the system:
w+y=40 (1)
9y=w (2)

In equation (1), let's replace w by it's value from equation (2) since w=9y.
We get: 9y+y = 40
10y=40
y=4
So there's 4 yellow cars.

In equation (1), let's replace y by it's value
w+4=40
w=40-4
w=36

Rafael counted 36 white cars.

You can re-check your answer:
4+36=40 (w+y=40)
9*4=36 (9y=w)
The answer has been approved.

Hope this Helps! :)
3 0
3 years ago
Read 2 more answers
When a shape becomes smaller, what transformation is happening?
andrezito [222]
Reflection: the object is reflected (or "flipped") across a line of reflection, which might be the x-axis, y-axis, or some other line. Dilation: the object stays the same shape, but is either stretched to become larger (an "enlargement") or shrunk to become smaller (a "reduction").
4 0
3 years ago
Sherry has a standard deck of cards. The deck has 52 total cards and contains 4 suits: hearts, clubs, diamonds, and spades. Each
tatyana61 [14]

Answer:

c) Events A and B are independent events.

The outcomes of events A and B are dependent on each other.

P(A and B)=P(A)•P(B)

Step-by-step explanation:

Given:

Total number, n = 52

Each suit contains 13 cards: 2 to 10, a jack, a queen, a king, and an ace.

Since there are 4 suits, it means the number of each card is four.

P(A) = event of picking a king

P(B) = event of picking a 3

Therefore the probability of picking a king = P(A) = \frac{4}{52}

Probability of picking a 3 = P(B) = \frac{4}{52}

Since only a card is picked, the probability a king is picked after picking a 3 is 0.

i.e P(A|B) = 0 ≠ P(A) = \frac{4}{52}

option A is wrong

The probability a 3 is picked after picking a king is 0.

i.e P(B | A) = 0 ≠ P(B) = \frac{4}{52}

option B is wrong

Events A and B are independent events.

The outcomes of events A and B are dependent on each other.

P(A and B)=P(A)•P(B)

Option C is correct.

7 0
3 years ago
There are two numbers that
GREYUIT [131]
-3 x -2 = 6
-3 + -2= -5
answer is -2
7 0
3 years ago
In triangle ΔABC, ∠C is a right angle and CD is the height to
Zina [86]

Answer:

m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles m\angle CDB=m\angle CDA=90°

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

m\angle A+m\angle B =90\\\alpha+m\angle B=90\\m\angle B=90-\alpha

From ΔCBD,

m\angle CBD is same as m\angle B.

So, m\angle CBD=90-\alpha

m\angle BCD+m\angle BDC =90\\m\angle BCD+90-\alpha=90\\m\angle BCD=\alpha

Now, from ΔCAD,

m\angle CAD is same as m\angle A

So, m\angle CAD=\alpha

m\angle CAD+m\angle ACD =90\\\alpha+m\angle ACD=90\\m\angle ACD=90-\alpha

Hence, the unknown angles of both the triangles are:

m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha

5 0
2 years ago
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