32. The Bolo Cavern outside of Vandalia is 421 ft below sea level. A little

LUCKY_DIMON [66]

100 because of complementary angles

8 0

2 years ago

A group incoming first-year students at Major University were surveyed in order to determine the factors that influenced their d

Ray Of Light [21]

Answer:

Step-by-step explanation:

This is a problem of SETS.

Start by listing out important data:

1. Total that said F = 55

2. Total that said P = 51

3. Total that said O = 61

4. F only = 9

5. F ∩ P ∩ O = 26 [NOTE: If you were to draw a Venn Diagram, 26 would be in the innermost circle because it comprises all three categories]

6. F ∩ P = 31

7. P only = 8

8. Students that said none of the 3 reasons = 4

QUESTIONS

1. How many said O and P? In other words, find the intersect of O and P. Find O ∩ P

2. How many said either F or O? [Answer to be gotten using a venn diagram] Find F ∪ P which translates to "F union P"

3. How many said F without saying P? [Answer to be gotten from the venn diagram as well]

4. How many students in total were surveyed? [HINT: Remember to include the 4 students that had none of the three options]

5 0

3 years ago

A wire that is 22 feet long connects the top of a pole to the ground. The wire is attached to the ground at a point that is 10 f

krok68 [10]

✰ Concept Used :-

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In this question, we can clearly observer that the diagram shows a right angled triangle. And, we have been provided with the value of base, and the value of hypotenuse, using the pythagoras theorem, now we can easily find out the value of the perpendicular i.e. the value of the side h. According to the pythagoras theorem, square of hypotenuse is equal to the sum of square of perpendicular and square of side respectively. Therefore, square of side is equal to the difference of square of hypotenuse and square of perpendicular.

⠀

✰ Given Information :-

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Hypotenuse = 22 ft.
Base = 10 ft.

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✰ To Find :-

⠀

The value of side or the perpendicular

⠀

✰ Formula Used :-

⠀

$\star \: \underline{ \boxed{ \purple { \sf {Side}^{2} = {Hypotenuse}^{2} - {Base}^{2} }}} \: \star$

⠀

✰ Solution :-

⠀

$\sf \longrightarrow {Side}^{2} = {(22 \: ft)}^{2} - {(10 \: ft)}^{2} \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {484 \: ft}^{2} - {100 \: ft}^{2} \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {384 \: ft}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \sqrt{ {384 \: ft}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \underline{ \boxed{ \frak{ \green{19.60 \: ft}}}} \: \star \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\$