The diagonal of a rectangle = sqrt(w^2 + l^2)
w = width
l = length
In this problem,
The diagonal = 20 in
w = x
l = 2x + 8
Let's plug our numbers into the formula above.
20in = sqrt((x)^2 + (2x + 8)^2)
Let's simplify the inside of the sqrt
20 in = sqrt(5x^2 + 32x + 64)
Now, let's square both sides.
400 = 5x^2 + 32x + 64
Subtract 400 from both sides.
0 = 5x^2 + 32x - 336
Factor
0 = (5x - 28)(x + 12)
Set both terms equal to zero and solve.
x + 12 = 0
Subtract 12 from both sides.
x = -12
5x - 28 = 0
Add 28 to both sides.
5x = 28
Divide both sides by 5
x = 28/5
The width cant be a negative number so now we know that the only real solution is 28/5
Let's plug 28/5 into our length equation.
Length = 2(28/5) + 8 = 56/5 + 8 = 96/5
In conclusion,
Length = 96/5 inches
Width = 28/5
Answer:
7x for the first one and −5x^8+12 for the second one
Step-by-step explanation:
please mark me brainliest :)
STEP 1:
Calculate total amount of ribbon
= 2 spools * 24 yards each
= 48 yards total
STEP 2:
Divide total yards (48 yards) by portion size (1/8 yard)
= 48 ÷ 1/8
to divide fractions, we multiply by the reciprocal/inverse of 1/8
= 48 * 8/1
= 48 * 8
= 384 bows
ANSWER: She can make 384 bows.
Hope this helps! :)
Answer:
n=-5
Step-by-step explanation:
first you have to distribute the 3 to the -6 and the 5. In return u will get -18n and 15. then you have to cancel like terms. then you have to add 18 to the 75 which gives you 93. then you divide -18 by 93 which gives you -5.166 repeating... so all you have to do is round. your final answer will be -5.
