Question

What's the vertex and axis of symmetry of y=2x+2)^2-4

Answer 1

Answer:

Vertex: V=(-2,-4)

Axis of symmetry: x=-2

Step-by-step explanation:

y=2(x+2)^2-4

y=a(x-h)^2+k

Vertex: V=(h,k)

-h=2→h=-2

k=-4

V=(-2,-4)

Axis of symmetry: x=h→x=-2