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alexandr402 [8]
3 years ago
14

What is the measure of ∠J?

Mathematics
1 answer:
sineoko [7]3 years ago
5 0

Answer:

6 cm

Step-by-step explanation:

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The following triangle shows the length of each side using expressions.
grigory [225]
Answer:

A). 2(2n+7)+3n

B). 2(2(8)+7)+3(8)
2(16+7)+ 24
2(23)+24
46+24
70
4 0
3 years ago
Find the area of a segment of a circle if its arc is 120 degrees and the radius is 3 inches.
Montano1993 [528]

Answer:<u> 9.42 inches</u>, 3π in terms of pi

Step-by-step explanation:

A full circle is 360 degrees, so if the segment has an arc of 120 degrees, it is 1/3 of a regular circle.

To find the area of a circle, we use the equation A = πr^2. In this case, we will divide the equation by 3 because we are only finding 1/ of a circle. So, our equation will be A  = (πr^2)/3.

Using 3.14 for π:

A  = (πr^2)/3.

A = (π3^2)/3

A = (π9)/3

A = 3π

A = 9.42

6 0
2 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
What is 4 2/7 as an improper fraction?<br> HURRYYYYYYY
Alika [10]

Answer: C. 30/7

Step-by-step explanation: To make an improper fraction out of a mixed one we have to multiply the denominator by the whole number (in this case is 4) and then add the numerator. So 7 x 4 = 28 + 2 = 30, so 30/7 would be the correct answer choice.

Hope this helps!

7 0
3 years ago
The length of a side of a regular hexagon is 6.8 cm, correct to one decimal place. Find the smallest possible perimeter of the l
marysya [2.9K]

Answer: 40.8cm

Step-by-step explanation:

A hexagon is a polygon that is made up of 6 sides. The perimeter of a regular hexagon is calculated by multiplying the side given by 6

Since the length of a side of a regular hexagon is 6.8 cm, the perimeter will be:

= 6 × 6.8

= 40.8cm

7 0
3 years ago
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