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cupoosta [38]
3 years ago
6

Timmy and Ben shared a bag of marbles. Timmy had 3/4 of what Ben had. When Ben gave 36 marbles to Timmy, Ben had 1/3 of what Tim

my had. How many marbles were there in the bag?
Mathematics
1 answer:
Svetllana [295]3 years ago
3 0

Let t be the inital number of Timmy's marbles, and b be the inital number of Ben's marbles.

At the beginning, "Timmy had 3/4 of what Ben had", which means

t = \cfrac{3}{4}b  \iff 4t=3b

(I wrote the equation in an equivalent form to avoid denominators)

Then, Ben gives 36 marbles to Timmy. So, now Ben has b-36 marbles, and Timmy has t+36 marbles. The new ratio is 1 to 3 in Timmy's favour, so we have

b-36 = \cfrac{t+36}{3} \iff 3(b-36) = t+36 \iff 3b-108 = t+36

(same as before)

So, we have the following linear system:

\begin{cases}4t=3b\\3b-108=t+36\end{cases}

From the first equation we know that 3b=4t, so the second equation becomes

4t-108=t+36 \iff 3t = 144 \iff t = \cfrac{144}{3} = 48

Now that we know the value for t, we can simply plug it into the first equation to get

3b = 4\times 48 = 192 \iff b=\cfrac{192}{3} = 64

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The given equations can be solved for y by substituting for x. The first equation is convenient for writing x in terms of y.

<h3>Solution</h3>

  x = 20 -y . . . . . . . subtract y from the first equation

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<em>Additional comment</em>

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Read 2 more answers
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