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Elza [17]
3 years ago
11

Java uses a left/right brace to mark the beginning/end of if-statement, compare this choice with the language which uses the "be

ginIF/endIF" keywords.
What language uses "beginIF/endIF" and how does it compate to Java left/right braces?
Computers and Technology
1 answer:
vovangra [49]3 years ago
3 0

Answer:

The answer is "Scribe markup language ".

Explanation:

Using the Code is the same processing in 2 stages which can be defined as follows;    

1. by using a scripting language to type a script.  

2. Proceed with both the file and produce the necessary documentation through your scribe compiler. If / endif starts with the reserved keyword.

by using BeginIf / EndIf, it is a type of multiple rules to make comments.  

In the beginning, if / endif, as well as java left-right braces, are no different.  

It uses two blocks or sentences for opening and closing.  

Both use the module to distinguish and both use feature isolation, process, and condition in a separate block when the compiler can understand what statement the method or section is using brackets.  

PL / SQL is also used for endif.  

If the statement to close.  

endif is used in c # as well  

If the rule is often used for closing.

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The only syntax error I saw was that the re pattern should have been double quoted.

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4 0
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Write a static method middleValue that takes three int parameters, and returns a int . It should return the middle value of the
anygoal [31]

We use if-else structure to check the each possible scenario and return the median accordingly in the middleValue() method. The main is also provided so that you can test the method.

Comments are used to explain the each line.

You may see the output in the attachment.

public class Main

{

public static void main(String[] args) {

   

    //call the method for different scenarios

    System.out.println(middleValue(1, 2, 3));

    System.out.println(middleValue(1, 3, 2));

    System.out.println(middleValue(2, 1, 3));

    System.out.println(middleValue(2, 3, 1));

    System.out.println(middleValue(3, 1, 2));

    System.out.println(middleValue(3, 2, 1));

 

}

       //method that takes three int and returns an int

public static int middleValue(int n1, int n2, int n3) {

    //set the median as n1

    int median = n1;

   

    //check the situation where the n1 is the highest

    //if n2 is greater than n2 -> n1 > n2 > n3

    //if not -> n1 > n3 > n2

    if(n1 > n2 && n1 > n3){

        if(n2 > n3)

            median = n2;

        else

            median = n3;

    }

   

    //check the situation where the n2 is the highest

    //if n3 is greater than n1 -> n2 > n3 > n1

    //if not -> n2 > n1 > n3

    //note that we set the median as n1 by default, that is why there is no else part

    else if(n2 > n1 && n2 > n3){

        if(n3 > n1)

            median = n3;

    }

   

    //otherwise, n3 is the highest

    //if n2 is greater than n1 -> n3 > n2 > n1

    //if not -> n3 > n1 > n2

    //note that we set the median as n1 by default, that is why there is no else part

    else{

        if(n2 > n1)

            median = n2;

    }

   

    return median;

}

}

You may see another if-else question at:

brainly.com/question/13428325

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Explanation: i hope im right ?

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