Answer:
Option B (Static NAT) would be the correct choice.
Explanation:
- Static NAT seems to be a method of NAT methodology used to navigate as well as monitor internet usage from some kind of specific public IP address to something like a private IP address.
- Everything always allows the provision of web access to technology, repositories including network equipment inside a protected LAN with an unauthorized IP address.
Some other decisions made aren't relevant to the situation in question. So the above alternative is indeed the right one.
Answer:
- #include <iostream>
- using namespace std;
- int main() {
- int number =5;
- if (number>=0&& number <=100){
- cout<<"passed.\n";
- }
- else{
- cout<<"failed.\n";
- }
- return 0;
- }
Explanation:
There where multiple errors in the code given in the questions
Line 1: Missing <iostream>
Line 5: The comparison operator was wrong correction is highlighted
Line 12 Missing closing brace for the main function
All the errors have been fixed and the code above compiles
Explanation:
The output of this program is 5 7, because the first time bruce is printed, his value is 5, and the second time, his value is 7. The comma at the end of the first print statement suppresses the newline after the output, which is why both outputs appear on the same line.
Here is what multiple assignment looks like in a state diagram:

With multiple assignment it is especially important to distinguish between an assignment operation and a statement of equality. Because Python uses the equal sign (=) for assignment, it is tempting to interpret a statement like a = b as a statement of equality. It is not!
First, equality is symmetric and assignment is not. For example, in mathematics, if a = 7 then 7 = a. But in Python, the statement a = 7 is legal and 7 = a is not.
Furthermore, in mathematics, a statement of equality is always true. If a = b now, then a will always equal b. In Python, an assignment statement can make two variables equal, but they don’t have to stay that way:
a = 5
Answer:
The answer is "Option A".
Explanation:
- In the given C++ Language program on line 8 compile-time error will occur, because in the code the conditional statement is used. In if block, we check two conditions together, which is the number variable value is greater than equal to 0 and check less than equal to 100.
- In this condition statement, a AND operator is used that execute when both condition is true, but in the last condition, we do not define a variable name that, checks value. That's why the program will give an error on line 8.
