Answer:
I believe the correct answer is<em> </em><u><em>C. mRnA translation. </em></u>
Explanation:
Because the gene expression is controlled on two levels. First, transcription is controlled by limiting the amount of mRNA that is produced from a particular gene. The second level of control is through post-transcriptional events that regulate the translation of mRNA into proteins.
Answer:
All of the options are true for a MRSA infection.
Explanation:
<em>Staphylococcus aureus</em> is one of the most frequent pathogens causing hospital and community infections. <em>S. aureus</em> can become very easy methicillin resistant (called MRSA isolates) and others beta-lactam antibiotics (are the ones widely used to treat infections) and usually can be resistant to other class of antibiotics, become a very strong bacteria making treatment options very limited. MRSA isolates can rapidly transfer the methicillin resistance to other species of S<em>taphylococcus</em> and some other bacteria. Also <em>S. aureus</em> can acquire other antibiotic resistant genes making a deadly bacterium for its strong resistance. It is in search how the bacterium acquire this antibiotics resistance ( and other virulence factors genes) and the mechanism involve to develop new drugs to treat MRSA infections with the hope that can´t develop resistance to this new drugs.
The proposed kingdom of euglenozoa includes protists with one or two flagella emerging from an anterior pocket
This flagella give them the ability to swim/moved throughout the water where they usually live
hope this helps
thin walls.
a moist inner surface.
a huge combined surface area.
Answer:
a. Ligase
b. Ligase (
it's repeated)
Explanation:
DNA synthesis begins, therefore, by synthesizing a short segment of RNA called a primer, which primer is synthesized by an enzyme called Primasa. Primasa is an RNA polymerase that uses DNA as a template. All fragments of Okazaki begin with a Primer. Subsequently, the DNA polymerase III Holoenzyme performs the synthesis of the corresponding DNA fragment until it reaches the next primer. At that time, DNA polymerase Ia replaces the DNA polymerase Holoenzyme III. The DNA polymerase I is responsible for removing the RNA primer through its 5'P-3'OH exonueotic activity and at the same time fills the hole by synthesizing DNA.
Finally, the two Okazaki fragments have to be joined, it is necessary to link the 3'OH end of a fragment with the 5'P of the next fragment. This work of sealing and joining the successive fragments is done by Ligase.
