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AysviL [449]
3 years ago
5

Prove that the vector product (also called the cross product) of vectors in 3 dimensional space, does not satisfy an associative

law for multiplication. (Hint: find a simple example of a cross product of 3 vectors that fails to be associative, showing the calculations.)

Mathematics
1 answer:
Elenna [48]3 years ago
3 0

Answer:

a = (1,0,0)

b = (1,1,0)

c = (1,1,1)

Step-by-step explanation:

In order to do this, we must find a counter example, that is to say, three vectors a, b,and c such that

(a x b) x c different to a x (b x c)

Let a, b and c be the vectors

a = (1,0,0)

b = (1,1,0)

c = (1,1,1)

Then (a x b) x c = (-1,-1,0)

See attachment 1

whereas

a x (b x c) = (0,0,1)

See attachment 2

So,

(a\times b)\times c \neq a \times(b\times c)

and the cross product is not associative.

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Write the equation in slope-intercept form of the line that has a slope of -7/8 and contains the point (-4, 9).
lubasha [3.4K]

Answer:

The equation of the line is y = -7/8x + 11/2

Step-by-step explanation:

Since we have the slope and a point to start, we can use point-slope form to find the equation.

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6 0
3 years ago
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
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