Answer: 30
Step-by-step explanation:
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
22,200 words per hour
step-by-step explanation:
60 minutes per hour
370 words per minute
370(60)
22,200
Answer:
Step-by-step explanation:
11.9 divided by 7 = 1.7
She uses 1.7 yards per apron
Answer:
- 1 bus, 72 vans
- $6960 is the minimum cost
Step-by-step explanation:
A bus costs over $19 per student; a van costs less than $12 per student. The required number of students could be transported by 81 vans, but that requires 81 chaperones.
Since there are only 80, and a bus requires fewer chaperones per student, we can reduce the number of required chaperones to an acceptable level by employing one bus. 1 bus replaces 9 vans, and requires 1 less chaperone than 9 vans.
The minimum cost is 1 bus and 72 vans. That cost is $1200 +72×$80 = $6960.
