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3 years ago

I need help please!!!!!!!

Mathematics

1 answer:

Sholpan [36]3 years ago

7 0

First box:
(going diagonal from top left to bottom right):

9+0 = 9
0+7 = 7

v

4+4 = 8
4+5 = 9

v

6+3 = 9
3+6 = 9

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X^6+3x^3-5 <br> write the expression in quadratic form

Art [367]

Step-by-step explanation:

$v = {x}^{3} \\ {v}^{2} + 3v - 5 = 0 \\$

Solving this equation using the quadratic formula, we get two real solutions :

1.1926 or -4.1926

Now we know the values of v , we can calculate x since x is ∛ v

${x}^{6} + 3 {x}^{3} - 5 = 0$

$x = \sqrt[3]{1.1926} = 1.0605 \\ x = \sqrt[3]{ - 4.1926} = - 1.6125$

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3 years ago

Explain with example of why 2^(-8) * 2^(-7) is equal to 2^(-15)

tatyana61 [14]

(-8)*(-7)=(-15)

the 2 in the beginning stays the same, and you multiply what’s in the parentheses to get (-15)

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3 years ago

Alex had $750,000 he lost 80% how many dollars did he lose

Stels [109]

Answer:

$600,000

Step-by-step explanation:

GIven;

Alex had $750,000 he lost 80%

To Find;

How many dollars did he lose

Solve;

$750,000 * 80% = 600,000

Hence, Alex lost $600,000.

<em>~Learn with Lenvy~</em>

8 0

2 years ago

Read 2 more answers

10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the

Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

$H_0: \mu = 0$

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

$H_1: \mu > 0$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

In this problem, the parameters are given as follows:

$\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50$ .

Hence, the test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}$

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by $t^{\ast} = 2.4$ .

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

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2 years ago

The Australian Open is the first of the four Grand Slam professional tennis events held each year. Victoria Azarenka beat Maria

klasskru [66]

Answer:

asnwer is B

Step-by-step explanation:

mark BRAINLIEST

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3 years ago