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3 years ago

Find the y intercept of (-2,5) and (3,25)

Mathematics

1 answer:

Alex777 [14]3 years ago

7 0

Answer:

The y-intercept is (0, 13).

Step-by-step explanation:

First finf the equation of the line:

The slope = (25- 5) / (3 - -2)

= 20/5

= 4

So its equation is

y - 5 = 4(x + 2)

y = 4x + 13

The y-intercept occurs when x = 0

so y-intercept = 4(0) + 13.

It's (0, 13).

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Answer:

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3 years ago

Solve the equation on the interval [0,2π). 7 sec x-7=0, x=?

Oksanka [162]

$\huge \bf༆ Answer ༄$

Let's solve ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:7 \sec(x) - 7 = 0$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:7 \sec(x) = 7$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: \sec(x) = 7 \div 7$

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2 years ago

Which pair of numbers are opposites? A. 7 and –7 B. 4 and C. 9 and D. 7 and 49

NARA [144]

Answer:

Step-by-step explanation:

7 and -7 are the opposite on the number line

7 0

3 years ago

Read 2 more answers

Please answer letters A and B

omeli [17]

C & D my dudeo

Oh no! Something went wrong while adding your answer
It's too short. Write at least 20 characters to explain it well.

3 0

3 years ago

Find the sum and the product of the roots of the equation: x^2−37x+27=0

lawyer [7]

Answer:

Sum of the Roots = 37

Product of the Roots = 27

Step-by-step explanation:

Here, the given expression is $x^{2} - 37x + 27 = 0$

Now the general Quadratic Equation is of the form:

$ax^{2} + bx + c = 0$

Here, Sum of the Roots = $-(\frac{b}{a} )$

and the Product of the Roots = $(\frac{c}{a} )$

So, comparing the general equation with the given equation, we get:

a = 1, b = -37 and c = 27

So, Sum of the Roots = $-(\frac{-37}{1} )$ = 37

and the Product of the Roots = $(\frac{27}{1} )$ = 27

6 0

3 years ago