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2 years ago

Solve the equation on the interval [0,2π). 7 sec x-7=0, x=?

Mathematics

1 answer:

Oksanka [162]2 years ago

8 0

$\huge \bf༆ Answer ༄$

Let's solve ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:7 \sec(x) - 7 = 0$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:7 \sec(x) = 7$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: \sec(x) = 7 \div 7$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: \sec(x) = 1$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = 0$

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an encyclopedia salesman earns a base pay of $23,900 per year and a commission of 11% of all sales made. If he sold $35,100 wort

serious [3.7K]

Answer:

27761

Step-by-step explanation:

find 11% of $35,100

then add it to 23900

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3 years ago

The profit that the vendor makes per day by selling x pretzels is given by the function P(x) = - 4x +2,400x - 400. Find the numb

never [62]

We have been given that the profit that the vendor makes per day by selling x pretzels is given by the function $P(x)=-4x^2+2400x-400$ . We are asked to find the number of pretzels that must be sold to maximize profit.

First of all, we will find the derivative of our given function.

$P'(x)=-4\cdot 2x^{2-1}+2400$

$P'(x)=-8x+2400$

Now, we will find the critical point by equating derivative with 0 as:

$-8x+2400=0$

$-8x+2400-2400=0-2400$

$-8x=-2400$

$\frac{-8x}{-8}=\frac{-2400}{-8}$

$x=300$

Therefore, the company must sell 300 pretzels to maximize profit and option B is the correct choice.

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3 years ago

Please help me. question is "solve each system of linear equations by substitution"

tigry1 [53]

Answer:

(-9,-7)

Step-by-step explanation:

Since x = 2y+5,

substitute that into the other equation. Then you have

3(2y+5)-5y = 8

6y+15-5y = 8

y = -7

so, x = 2(-7)+5 = -9

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3 years ago

Select all that apply. Which of the following are equivalent? a. 6 oranges for 2 dollars b. 3 oranges for a dollar c. 3 dollars

Yuri [45]

This question is asking you to compare ratios, and in order to do that, all you have to is simplify the fractions into a unit rate (meaning that you get x number of oranges for $1.00). Remember, unit rates <em>always</em> have a denominator of one. If the unit rates in these expressions are determined to be the same, then the price of oranges is equivalent.

6 oranges for $2.00 = 6/2 = 3 oranges for $1.00

3 oranges for $1.00 = 3/1 = 3 oranges for $1.00

1 orange <em>and </em> $3.00 = unknown, more than $3.00

9 oranges for $3.00 = 9/3 = 3 oranges for $1.00

answer: A. 6 oranges for $2, B. 3 oranges for $1, and D. 9 oranges for $3

hope the helps!

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3 years ago

Question 1 of 10

julia-pushkina [17]

Answer:

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Step-by-step explanation:

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3 years ago